1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
VLD [36.1K]
3 years ago
7

Chromic acid, H2CrO4, is a strong oxidizing agent that oxidizes primary and secondary alcohols into carboxylic acids and ketones

, respectively. Which technique would be most useful for monitoring the progress of the reaction
Chemistry
1 answer:
amm18123 years ago
7 0

Answer:

Thin-layer chromatography

Explanation:

Here in this question, we are concerned with giving the best technique that could be use for monitoring the progress of the reaction that involves the oxidation of alcohols.

The most useful technique here for monitoring the progress of the reaction would be the thin layer chromatography.

Firstly, we should know the reason why we are using a chromatographic technique. This is intuitive. The reason is that the oxidizing agent being used is a colored substance. So basically, the progress of the oxidation reaction would solely rest on the fact that we have a decrease in color saturation of the said oxidizing agent.

This is best done using the thin layer chromatography because we have a mobile phase that moves quickly over the stationary phase and asides this, it moves evenly.

This makes the fact that color changes can be quickly and easily identified and we can tell if the oxidation reaction has gone to completion or not

You might be interested in
2. Most species fail in new environments because of.
EastWind [94]

Most species fail in new environments because of: Low population numbers

8 0
3 years ago
100 PIONTSSSSS HELP ASAP
valina [46]

Left Panel

Short answer A

<em><u>Solution</u></em>

Since you have been given choices, my sloppy numbers will do, but it anyone is going to see this, YOU SHOULD CLEAN  THEM UP WITH THE NUMBERS THAT COME FROM YOUR PERIODIC TABLE.

Equation

Sodium Phosphate + Calcium Chloride ===> Sodium Chloride + Calcium Phosphate.

Na3PO4 + CaCl2 ===> NaCl + Ca3(PO4)2

<em><u>Step One</u></em>

Balance the Equation

2Na2PO4 + 3CaCl2 ==> 6NaCl + Ca3(PO4)2

<em><u>Step Two</u></em>

Find the molar mass of CaCl2

Ca = 40

2Cl = 71

Molar Mass = 40 + 71 = 111 grams/mole

<em><u>Step Three</u></em>

Find the number of moles of CaCl2

Given mass = 379.4

Molar Mass = 111

moles = given Mass / molar Mass

moles of CaCl2 = 379.4/111 = 3.418 moles

<em><u>Step Four</u></em>

Find the number of moles of Ca3(PO4)2 needed.

This requires that you use the balance numbers from the balanced equation.

For every 3 moles of CaCl2 you have, you get 1 mole of Ca3(PO4)2

n_moles of Ca3(PO4)2 = 3.418 / 3 = 1.13933 moles

<em><u>Step Five</u></em>

Find the molar mass of Ca3(PO4)2

From the periodic table,

3Ca = 3 * 40 = 120

2 P  = 2 * 31 =    62

8 O = 8 * 16   =128

Molar Mass = 120 + 62 + 128= 310 grams per mole.

<em><u>Step Six</u></em>

1 mole of Ca3(PO4)2 has a molar mass of 310 gram

1.13933 moles of Ca3(PO4)2 = x

x = 1.13933 moles * 310 grams /mole

x = 353.2 grams. As you can see, even with my rounding I'm only out 0.3 of a gram. DON'T FORGET TO PUT THIS TO THE PROPER SIG DIGS IF SOMEONE ELSE IS GOING TO SEE IT.

Middle Panel

Short Answer C

Equation

2HCl + Mg ===> H2 + MgCl2

The object of the first part of the game is to find the number of moles of H2.

<em><u>Step One</u></em>

Find the moles of HCl

1 mole HCl = 35.5 + 1 = 36.5

n = given mass divided by molar mass

n = 49 grams / 36.5 = 1.34 moles.

The balanced equation tells you that for ever mole of H2 produced, you need 2 moles of HCl. That's what the balance numbers are for.

So the number of moles of H2 is 1.34 / 2 = 0.671 moles of H2.

Now we come to Part II. We have to use an new friend of yours that I have seen only once before from you.

Find V using PV = nRT

R is going to be in kPa so the value of R = 8.314

V = ???

n = 0.671 moles

T = 25 + 273 = 298oK

P = 101.3 kPa

101.3 * V= 0.671*8.314 * 298

V = 0.671 * 8.314 * 298 / 101.3

V = 16.4

The answer is C and again, I have rounded almost everything except R, although it can go out to 8 places.

Right Panel

I can't see the panel. I don't know what the problem is. Never mind I got it. I'm going to be a little skimpy on this one since I've done two like it and they are long.

LiOH + HBr ===> LiBr + H2O and the equation is balanced.

You have to figure out the moles of LiOH and HBr. Use the LOWEST number of moles

n_LiOH = given mass / molar mass = 117/(7 + 16 + 1) = 117 / 24 = 4.875 moles

n_HBr = given mass / molar mass =  141/(1 + 80) = 141 / 81 = 1.741 moles

HBr is the lower number. That's all the LiBr you are going to get is 1.741. There is no adjustment to be made from the balance equation.

n = given mass / molar mass  multiply both sides by the molar mass

n * Molar mass (LiBr) = n * (7 + 80) = 1.741 * 87 = 151 grams of

The answer is C


6 0
3 years ago
2 unicellular no autotrophic It uses a flagellum. A. Kingdom animalia B. kingdom fungi B. kingdom plantae D. kingdom protista
Pachacha [2.7K]
I know the answer to the question
8 0
3 years ago
When the electron of a hydrogen atom moves into a higher energy orbit, what is the state of the atom?
faltersainse [42]
Answer is: <span>excited state.
In </span>excited state, hydrogen has<span> higher </span>energy<span> than in the </span>ground state (state with lowest energy). H<span>ydrogen atom has one </span>electron<span> in the lowest possible </span>orbit<span> (1s), when atom absorbs</span><span> energy</span><span>, the electron move into an excited state (quantum numbers greater than the minimum possible). </span>Electron lifetime in excited state is short.
4 0
3 years ago
Si 100 monedas tienen una masa total de 226.13g. Cual es la masa de una moneda
galben [10]

The mass of a coin : 2.2613 g

<h3>Further explanation  </h3>

Algebraic expressions in mathematics are a combination of coefficients, numbers, variables, constants and arithmetic operations such as addition, subtraction, multiplication, and division.  

The main composition of algebraic expressions are:  

  • 1. phrases  

algebraic forms separated by arithmetic operations  

consists of one phrase (monomial) to many phrases (polynomial)  

  • 2. variables  

is a value that can be changed, can be in the form of letters, for example, x, y, a, b, etc.  

  • 3. constants  

is a fixed value, can be a number  

  • 4. arithmetic operations ⇒ +, - , : , x

<em>If 100 coins have a total mass of 226.13g. What is the mass of a coin</em>

We can make this statement in the form of an algebraic equation :

100 coins=226.13 g

then the mass of a coin :

\tt \dfrac{1}{100}\times 226.13~g=2.2613~g

5 0
3 years ago
Other questions:
  • What was Aristotle’s theory of matter? Was it atomistic or formal?
    10·1 answer
  • When you add energy to matter the particles move
    6·1 answer
  • 5. Consider the process where nA mol of gas A initially at 1 bar pressure mix with nB mol of gas B also at 1 bar to form 1 mol o
    5·1 answer
  • The major source of aluminum in the world this bauxite (mostly aluminum oxide). It’s thermal decomposition can be represented by
    15·1 answer
  • The slope of the velocity versus time graph of an object with positive velocity and acceleration is ________, and the shape of t
    11·1 answer
  • What type of crystal is limestone
    7·1 answer
  • Potassium hydroxide reacts with hydrochloric acid to form salt and water.
    14·2 answers
  • Which statement correctly compares what occurs when molecules absorb photons in the microwave region with what occurs when molec
    6·2 answers
  • How many formula units are there in 103 g of NaCl?
    14·1 answer
  • At the end of chemical reactions, what is the total mass of the reactants compared to the total mass of the products?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!