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3 years ago

5

Ned tightens a bolt in his car engine by exerting 15 N of force on his wrench at a distance of 0.45m from the fulcrum. How much

torque must Ned produce to turn the bolt?

1 answer:

____ [38]3 years ago

8 0

Answer:

$T = 6.75\,N\cdot m$

Explanation:

Vectorially speaking, torque is the cross product between force and distance from fulcrum. Its magnitude is equal to the following expression:

$T = F\cdot r \cdot \sin \theta$

$T = F_{\bot} \cdot r$

Let assume that force is perpendicular to the distance from the fulcrum. So, the torque needed to turn the bolt is:

$T = (15\,N)\cdot (0.45\,m)$

$T = 6.75\,N\cdot m$

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What is the total moved without regard to direction

soldi70 [24.7K]

The entire motion of an object, regardless of direction.

In physics, motion is that the phenomenon in which an object changes its position with respect to time. Motion is mathematically described in terms of displacement, distance, velocity, acceleration, speed, and frame of regard to an observer and measuring the change in position of the body relative to that frame with change in time. The branch of physics describing the motion of objects without regard to their cause is called kinematics, while the branch studying forces and their effect on motion are named dynamics.

If an object isn't changing relative to a given frame of reference, the thing is said to be at rest, motionless, immobile, stationary, or to possess a constant or time-invariant position with reference to its surroundings. Modern physics holds that, as there's no absolute frame of reference, Newton's concept of absolute motion can't be determined

To learn more about motion from the given link:

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1 year ago

You have a ball with a mass 1.3 kg tied to a rope, and you spin it in a circle of radius 1.8m. If the ball is moving at a speed

BlackZzzverrR [31]

Answer:

$6.5\; {\rm N}$ .

Explanation:

When an object travel at a speed of $v$ in a circle of radius $r$ , the (centripetal) acceleration of that object would be $a = (v^{2} / r)$ .

In this question, the ball is travelling at $v = 3\; {\rm m\cdot s^{-1}}$ in a circle of radius $r = 1.8\; {\rm m}$ . The (centripetal) acceleration of this ball would be:

$\begin{aligned} a &= \frac{v^{2}}{r} \\ &= \frac{(3\; {\rm m\cdot s^{-1}})^{2}}{1.8\; {\rm m}} \\ &= 5\; {\rm m\cdot s^{-2}}\end{aligned}$ .

By Newton's Laws of Motion, for an object of mass $m$ , if the acceleration of that object is $a$ , the net force on that object would be $m\, a$ . Since the acceleration of this ball is $a = 5\; {\rm m\cdot s^{-2}}$ , the net force on this ball would be:

$\begin{aligned} F &= m\, a \\ &= 1.3\; {\rm kg} \times 5\; {\rm m\cdot s^{-2}} \\ &= 6.5\; {\rm N} \end{aligned}$ .

7 0

2 years ago

A motor lifts a 500kg elevator a height of 100 m at a constant speed in 50 secs. How much power did the motor supply

MA_775_DIABLO [31]

Answer:

9,800 watts

Explanation:

The first step is to calculate the force

F= mg

= 500 × 9.8

= 4,900 N

The next step is to calculate the work done

= 4,900 × 100

= 490,000 joules

Therefore the power can be calculated as follows

Power= work done /time

= 490,000/50

= 9,800 watts

3 0

2 years ago

Two copper rods are separated by a small gap at B. Rod AB has a diameter of 200mm and rod BC has a diameter of 150mm. Find the f

gulaghasi [49]

Answer:

A)3.8196 * $10^{9}$ Newtons B) 2.153 * $10^{9}$ Newtons

Explanation:

Force = Pressure * Area.

Pressure is given as 120GPa

Area = Cross Sectional Area of Rod = Area Of A circle = π $R^{2}$ .

Area Expansivity β = $\frac{Change in Area}{Original Area * Temperature Rise}$

Area Expansivity β = 2α

α = 16.9x10-6/ ° C.

Radius of Rod AB = Half 0f Diameter, 200mm = $\frac{0.2m}{2}$ = 0.1 m

Radius of Rod BC = Half Of Diameter, 150mm = $\frac{0.15}{2}$ = 0.075 m.

Note: To convert from millimeter to meter you divide by 1000.

Area of Rod AB = π * $0.1^{2}$ = 0.0314 $m^{2}$

Area of Rod BC = π * $0.075^{2}$ = 0.0177 $m^{2}$ .

Change in Area = 2α * Original Area * Temperature Rise. Therefore for

Rod AB = 2 * 16.9* $10^{-6}$ * 0.0314 * 30 = 3.183 * $10^{-5}$ $m^{2}$ .

For Rod BC we have = 2 * 16.9* $10^{-6}$ * 0.0177 * 30 = 1.794∈-5 $m^{2}$ .

The forces on each rods will be given by.

Force AB = Pressure * Area of Rod AB

= 120GPa * 3.183 * $10^{-5}$ gives 3.8196 * $10^{9}$ Newtons.

Force BC = Pressure * Area of Rod BC

= 120GPa * 1.794 * $10^{-5}$ gives 2.153 * $10^{9}$ Newtons

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2 years ago

Dimension of radius of sphere

Readme [11.4K]

Answer:

The dimension is L

Explanation:

Dimension analysis is a method of representing quantities majorly with respect to some fundamental quantities of mass (M), length (L), time (T).

A sphere has a definite volume which relates to its radius by:

V = $\frac{4}{3}$ $\pi$ $r^{3}$

In this equation $\pi$ is a dimensionless quantity, and the unit of v is $m^{3}$ .

But, metre is a measure of length, thus it has a dimension of L.

So that,

$m^{3}$ ≅ $L^{3}$

Then,

$L^{3}$ = $r^{3}$

Find the cube root of both sides to have,

r = L

Therefore, the dimension of the radius of a sphere is L.

5 0

3 years ago