1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brrunno [24]
3 years ago
6

A child pushes a toy box across the floor in 5 seconds. If he did 30 J of work on the toy box, what amount of power was required

to complete this action?
6 watts
25 watts
150 watts
35 watts
Physics
2 answers:
weqwewe [10]3 years ago
8 0
6 WATTS, WNJOY MY FRIEND
s2008m [1.1K]3 years ago
4 0
My answer is 6 watts because 30J/5s is 6
You might be interested in
Gantt charts are A. widely used network techniques. B. not widely used. C. planning charts used to schedule resources and alloca
kotykmax [81]

Answer:

planning charts used to schedule resources and allocate time is the correct answer

Explanation:

  • Gantt Charts are a project planning tool used to track the projects from the start to endpoint.
  • Gantt charts are used for the preparation and planning of the projects.
  • By using Gantt charts we can assess how much time a project would take to complete and we can also determine resources required with the help of Gantt charts.

6 0
3 years ago
Two objects are moving at equal speed along a level, frictionless surface. the second object has twice the mass of the first obj
Zarrin [17]

first object gors highest

second object goes lowest.


5 0
3 years ago
A large fake cookie sliding on a horizontal surface is attached to one end of a horizontal spring with spring constant k = 440 N
irinina [24]

Answer:

a) 0.275 m b) 13.6 J

Explanation:

In absence of friction, the energy is exchanged between the spring (potential energy) and the cookie (kinetic energy), so at any point, the sum of both energies must be the same:

E = ½ kx2 + ½ mv2

If we take as initial state, the instant when the cookie is passing through the spring’s equilibrium position, all the energy is kinetic, and we know that is equal to 20.0 J.

After sliding to the right, while is being acted on by a friction force, it came momentarily at rest. At this point, the initial kinetic energy, has become potential elastic energy, in part, and in thermal energy also, represented by the work done by the friction force.

So, for this state, we can say the following:

Ki = Uf + Eth = ½* k*d2 + Ff*d

20.0J = ½ *440 N/m* d2 + 11.0 *d, where d is the compressed length of the spring, which is equal to the distance travelled by the cookie before coming momentarily at rest.

We have a quadratic equation, that, after simplifying terms, can be solved as follows, applying the quadratic formula:

d = -0.05/2 +/- √0.090625 = -0.025 +/- 0.3 = 0.275 m (we take the positive root)

b) If we take as our new initial status the moment at which the spring is compressed, and the cookie is at rest, all the energy is potential:

E = Ui = 1/2 k d²

In this case, d is the same value that we got in a), i.e., 0.275 m (as the distance travelled by the cookie after going through the equilibrium point is the same length that the spring have been compressed).

E= 1/2 440 N/m . (0.275)m² = 16.6 J

When the cookie passes again through the equilibrium position, the energy will be in part kinetic, and in part, it will have become thermal energy again.

So, we can write the following equation:

Kf = Ui - Ff.d = 16.6 J - 11.0 (0.275) m = 16.6 J - 3.03 J = 13.6 J

3 0
3 years ago
A quantity found by multiplying the force by the distance moved
Andrej [43]
The quantity that is calculated from the product of the force and the distance traveled due to the force is called work.  It has SI units of Joules (J) which is equivalent to Newton-meter (N-m). It is the energy that happens when an object is being moved by an external force.
7 0
3 years ago
What is the difference in Neil Armstrong’s weight on the moon and on earth? Neils mass is 160kg including his spacesuit and back
Len [333]

Explanation:

Given parameters:

Mass of Neil Armstrong = 160kg

Gravitational pull of earth = 10N/kg

Moon's pull = 17% of the earth's pull

Unknown:

Difference between Armstrong's weight on moon and on earth.

Solution:

To find the weight,

   Weight = mass x acceleration due to gravity = mg

Moon's gravitational pull = 17% of the earth's pull = 17% x 10 = 1.7N/kg

Weight on moon = 160 x 1.7 = 272N

Weight on earth = 160 x 10 = 1600N

The difference in weight = 1600 - 272 = 1328N

The weight of Armstrong on earth is 1328N more than on the moon.

Learn more:

Weight and mass brainly.com/question/5956881

#learnwithBrainly

3 0
3 years ago
Other questions:
  • Taking the resistivity of platinoid as 3.3 x 10-7 m, find the resistance of 7.0 m of platinoid wire of average diameter 0.14 cm.
    12·1 answer
  • Please help!
    5·2 answers
  • You add 500 mL of water at 10°C to 100 mL of water at 70°C. What is the
    10·1 answer
  • A stack of bricks weighs 170 KN (Kilo-newtons). The stack exerts 180 KPa (Kilo-pascals) of pressure on the ground. What is the a
    15·1 answer
  • A 243 mL cup of whole milk contains about 45 mg of cholesterol. Express the cholesterol concentration of the milk in kilograms p
    13·1 answer
  • A motorcycle has a magnet attached to the rim of its front wheel. The front tire has a diameter of 60 cm. A magnetic pickup is a
    15·1 answer
  • Find the acceleration of a car that can go from rest to 50 km/h in 13 s
    12·1 answer
  • Please I need help ill give u 50 points
    14·1 answer
  • The tiny planet Mercury has a radius of 2400 km and a mass of 3.3 times 10^23 kg.
    13·2 answers
  • ] After treatment, hospital equipment may become contaminated.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!