Answer:
6
Not perpendicular
Step-by-step explanation:
Generally, when we have two vectors, (x1, x2, x3...xn) and (y1, y2, y3...yn) the inner product is given by x1*y1+(x2*y2)+(x3*y3).....(xnyn)
If the above sum is zero then the two vectors are perpendicular else they are not.
Given (3, 1, 4) and (2, 8, -2)
The inner product will be
(3*2)+(1*8)+(4*-2)=6+8-8=6
The inner product is 6 hence not perpendicular.
A. 4
-8+4=-4
B-1
-8+-1=-9
C. 2
-8+2=-6
D. -8+0=-8
The answer is A
Answer:
c 3/2
Step-by-step explanation:

Let's see what's the domain and range for the given function ~
![\qquad \tt \dashrightarrow \:domain \in [ -5 , 4 ]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Cdashrightarrow%20%5C%3Adomain%20%5Cin%20%5B%20-5%20%2C%204%20%5D%20)
or

Because domain = all values of x between its maximum (4) and minimum (-5) value [ including them ]
![\qquad \tt \dashrightarrow \:range \in[ -4 , 9 ]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Cdashrightarrow%20%5C%3Arange%20%5Cin%5B%20-4%20%2C%209%20%5D)
or

Because range = all values of y between its maximum (9) and minimum (-4) value [ including them ]
Answer:
No
Step-by-step explanation:
it doesnt add up to 180 degrees