What is the magnitude of the force a charge 25uc exerts on a charge 3mc 35 cm away?

Giving a test to a group of students, the grades and gender are summarized belowGrades vs. Gender ABCMale10316Female465If one st

strojnjashka [21]

Answer:

20.45%

Explanation:

The probability that the student got a B is

$\frac{total\#of\text{ students that got B}}{\text{total students }}\times100\%$

Now, how many students are there in total?

The answer is

$10+3+16+4+6+5=44\; \text{students}$

How many students got a B?

The answer is

$3+6=9\; \text{students}$

therefore, the probability that the student has got a B is

$\frac{9\text{ students }}{44\text{ students }}\times100\%=20.45\%$

Hence, the probability that a student has got a B is 20.45%

5 0

1 year ago

Stars are called blackbody radiators because they

scoundrel [369]

The answer is D) absorb most of the light that falls on them

A blackbody is an object that absorbs most (theoretically all) of the light that falls on it. Stars are called black bodies because they demonstrate something close to this property. Why do they appear white and not black? As black body radiators heat up, they slowly turn from black to grey to white, according to the human eye. Since stars are incredibly hot, they appear white to us.

8 0

3 years ago

A farmer lifts his hay bales into the top loft of his barn by walking his horse forward with a constant velocity of 1 ft/s. Dete

Lesechka [4]

Answer:

The velocity of the hay bale is - 0.5 ft/s and the acceleration is $6.25\times 10^{- 3} ft/s^{2}$

Solution:

As per the question:

Constant velocity of the horse in the horizontal, $v_{x} = 1 ft/s$

Distance of the horse on the horizontal axis, x = 10 ft

Vertical distance, y = 20 ft

Now,

Apply Pythagoras theorem to find the length:

$20^{2} + 10^{2} = l^{2}$

$l^{2}= 500$

Now,

$x^{2} + y^{2} = 500$ (1)

Differentiating equation (1) w.r.t 't':

$2x\frac{dx}{dt} + 2y\frac{dy}{dt} = 0$

$x\frac{dx}{dt} = - y\frac{dy}{dt}$

where

$\frac{dx}{dt}$ = Rate of change of displacement along the horizontal

$\frac{dy}{dt}$ = Rate of change of displacement along the vertical

$v_{x}$ = velocity along the x-axis.

$v_{y}$ = velocity along the y-axis

$xv_{x} = -yv_{y}$

$v_{y} = - 10\times \frac{1}{20} = - 0.5 ft/s$

$|v_{y}| = 0.5\ ft/s$

Acceleration of the hay bale is given by the kinematic equation:

$v_{y}^{2} = u_{y} + 2ay$

$(-0.5)^{2} =0 + 2ay$

$0.25 = 2ay$

$\frac{0.25}{2y} = a$

$a = \frac{0.25}{2\times 20} = 6.25\times 10^{- 3} ft/s^{2}$

7 0

3 years ago

Parallel to the handle, what is the force of friction acting on the suitcase?

mrs_skeptik [129]

<span>Lets call F the friction force which will act horizontally backwards.

As you are travelling at a constant velosity horizontally there is no overall resultant force in this direction.

ie. the force you pull with will be equal to the friction force resisting you. (you will initially have to have pulled with a greater force than the friction to get the suitcase moving)

the value of your force pulling is 60 cos26.9 (horizontally) - you should have learnt about resolving forces.

this must be equal to F

so

F=60cos26.9
F=53.5N

hope this helps you
please mark this as brainliest answer</span>

5 0

3 years ago

The hockey stick hits the puck forward. Give the reaction force

weqwewe [10]

I think the puck pushes the stick backwards

3 0

3 years ago