In a closed system, energy in form of heat (work) can be exchanged but not matter.
The answer to your question is C.
Hope it helped!
Answer:
20.4e18 electrons/second ≈ 2e19 electrons/second
Explanation:
Hi!
To solve this problem we are going to use Omh's Law:
V = RI
And the relation ship between the resistance R and conductivity:
R = L/(σA)
*here we are considering a omhic material*
The conductance σ is related to electron mobility and electron density by:
σ = nμ
Replacing all these relations in the omhs law, we get:
V = (LI)/(σA)
We know that both wire are subject to the same electric field, therefore V is the same for both, moreover, since no additional info for the length of the wires is given we are going to consider that L is the same for both. Therefore
This means that:
From the relation of the conductance and electron mobility and density, and the data given to us, we know that:
Also
Therefore:
That is:
Since I_A = 3*10^18 e/s
I_B = 20.4*10^18 e/s
Answer:
The fish is experiencing a water pressure of 502.8 kPa.
Explanation:
The water pressure the fish is experiencing can be found as follows:
(1)
Where:
g: is the gravity = 9.81 m/s²
h: is the height (depth) = 50.0 m
ρ: is the seawater's density = 1.025 g/cm³
By replacing the above values into equation (1) we have:
Therefore, the fish is experiencing a water pressure of 502.8 kPa.
I hope it helps you!
Answer:
X = 69.1 x 10⁻⁶ m = 69.1 μm
Explanation:
The relationship between the motion of the moveable mirror and the fringe count of the Michelson's Interferometer is given by the following formula:
d = mλ/2
where,
d = distance moved by the mirror = X = ?
m = No. of Fringes counted = 246
λ = wavelength of light entering interferometer = 562 nm = 5.62 x 10⁻⁷ m
Therefore,
X = (246)(5.62 x 10⁻⁷ m)/2
Therefore,
<u>X = 69.1 x 10⁻⁶ m = 69.1 μm</u>