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Anettt [7]
3 years ago
13

Determine the magnitude and direction of the force on a 200 m power line carrying a current of 5.0-A due west in a magnetic fiel

d of 6.0 μΤ in a direction of 30°, north of east.
Physics
1 answer:
bogdanovich [222]3 years ago
7 0

Answer:

Explanation:

l = 200 m

i = 5 A west

B = 6 micro Tesla direction 30 degree north of east

angle between length vector and the magnetic field vector = 180 - 30 = 150 degree

Write the length and the magnetic field in the vector form

\overrightarrow{l}=- 200 \widehat{i}metre

\overrightarrow{B}= 6\times 10^{-6}\left ( Cos30\widehat{i}+Sin30\widehat{j} \right )Tesla

\overrightarrow{B}=\left ( 5.2\widehat{i}+3\widehat{j} \right )\times 10^{-6}Tesla

\overrightarrow{F} = i \overrightarrow{l}\times \overrightarrow{B}

\overrightarrow{F} = 5\times \left ( -200\widehat{i} \right )\times \left ( 5.2\widehat{i}+3\widehat{j} \right )\times 10^{-6}

\overrightarrow{F} =- 3\times 10^{-3}\widehat{k}Newton

Thus, the magnitude of force is 3 x 10^-3 newton and it is directed towards negative z axis direction.

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Answer: a=-2.4525 m/s^2

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A brick of mass 2.0kg is at rest. It falls to the ground through a
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Answer:

I may not have the answer so i'll just give up some hints.

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A small boy is playing with a ball on a stationary train. If he places the ball on the floor of the train, when the train starts moving the ball moves toward the back of the train. This happened due to inertia

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To learn more about inertia here :

brainly.com/question/11049261

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