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Contact [7]
3 years ago
12

Write 200m and 2 ×10^4m in kmwrite 5000ms and 5×10^7ms in seconds

Physics
1 answer:
WINSTONCH [101]3 years ago
5 0

Answer:

a) 20.2 kilometers

b)50 005 seconds

Explanation:

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What two types of scientific knowledge can be expressed as mathematical equations? (Please don't tell me the answer could you pl
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An example would be 2 types of motion. It could be rectilinear or projectile motion. There are various equations for each type. Since you don't want me to tell you the answer, I could just express it in words. Then, it will be up to you to translate into mathematical equations.

For rectilinear motion, the distance traveled is equal to the initial velocity times the time, plus one-half of the acceleration times the square of the time. For projectile motion, the maximum distance is equal to the square of the initial velocity multiplied with the square of the sine of the launch angle, all over twice the gravity.
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Help!! If an atom has 7 protons and 8 neutrons, and is not in an excited state, how many electrons would Bohr say the atom has?
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What is Secular Music's instrument's?​
nasty-shy [4]

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Drums, harps, recorders, and bagpipes.

Explanation:

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A vector has an x-component
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Explanation:

The magnitude of a vector v can be found using Pythagorean's theorem.

||v|| = √(vₓ² + vᵧ²)

||v|| = √((-309)² + (187)²)

||v|| ≈ 361

You can find the angle of a vector using trigonometry.

tan θ = vᵧ / vₓ

tan θ = 187 / -309

θ ≈ 149° or θ ≈ 329°

vₓ is negative and vᵧ is positive, so θ must be in the second quadrant.  Therefore, θ ≈ 149°.

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3 years ago
If two point masses 1kg & 4kg are seperated by a distance of 2m. Magnitude of gravitational force exerted by 1kg on 4kg is ?
Aliun [14]

Answer:

  • F = G Newtons

Explanation:

Given:

  • Mass of 1st body = 1\:kg
  • Mass of 2nd body = 4\:kg

To Find:

  • Magnitude of gravitational force

Solution:

Here, we have a formula

  • F=\dfrac{G.M_{1}.M_{2}}{r^{2}}

<u>Substituting the values</u>

\implies\:\:F = \dfrac{G(1)(4)}{2^{2}}

\implies\:\:F = \dfrac{4G}{4}

\implies\:\:F = \dfrac{\cancel{4}G}{\cancel{4}}

\implies\:\:\red{F = G}

Know More:

The applied formula for the above solution is

{\boxed{F_{G}=\dfrac{G.M_{1}.M_{2}}{r^{2}}}}

where,

  • F_{G} = Gravitational force
  • G = Gravitational constant
  • M_{1} = mass of 1st body
  • M_{2} = mass of 2nd body
  • r = distance between two bodies
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