<span>NaOH + HCl → NaCl + H2O
1 mol 1 mol
</span>2.75 × 10⁻⁴ mol 2.75 × 10⁻⁴ mol
M(H2O) = 2*1.0 +16.0 = 18.0 g/mol
2.75 × 10⁻⁴ mol H2O * 18.0 g H2O/1 mol H2O = 4.95*10⁻³ g H2O
Answer:
The correct answer is c add more HCO3- by adding NaHCO3.
Explanation:
The reaction mentioned in the question is carried out by bicarbonate buffer system of our body to maintain the normal acid base balance.
Now concentration of the reactant (H2C03) is decreased then NaHCO3 should be added which undergo breakdown to release bicarbonate ions(HCO3-).
The released bicarbonate ions then reacts with H+ to form Carbonic acid(H2CO3).Thus homeostasis of H2CO3 is maintained.
<span>17.5 g
35 ppt stands for 35 parts per thousand. So let's convert that to a decimal number by taking 35 and dividing by 1000.
35/1000 = 0.035
Now multiply that number by the number of grams of seawater you have. So
0.035 * 500 g = 17.5 g
So you have 17.5 grams of salt when you have 500 grams of seawater.</span>
The empirical formula represents the simplest whole number shows the simplest whole number ratio of atoms in a compound. An example of this is the empirical formula for glucose (C₆H₁₂O₆) is C₃H₆O₃.
I hope this helps. Let me know if anything is unclear.
