Answer:
g(x) has the greater max: 11 versus 6
Step-by-step explanation:
One can readily discern the max value of the graph; it is 6 and occurs at x =1.
Regarding the function g(x) = (-1/2)x^2 + 4x + 3: Find the vertex, which also represents the max value:
Here the coefficients are a = -1/2, b = 4 and c = 3, so that the axis of symmetry is:
x = -b/(2a), which here is x = -4 / ( 2·[-1/2] ) = -4 / (-1) = 4
At x = 4, the function (y) value is
g(4) = (-1/2)(4)² + 4(4) + 3, or
g(4) = -8 + 16 + 3, or 11
This is greater than the max value of the graphed function.
Answer:
D
Step-by-step explanation:
D I believe this is correct
I think its 3:10, I haven't done ratios in a while.
Hope this helped :)
Use the distance formula
d = sqrt ((y2-y1)^2 + (x2-x1)^2))
= sqrt ( (5 sqrt2 - sqrt2)^2 + ( -3sqrt5 - sqrt5)^2)
= sqrt [( 4sqrt2)^2 + (4sqrt5)^2]
= sqrt (32 + 16*5) = sqrt 112 = sqrt16 * sqrt7 = 4 sqrt7
The answer is 4 sqrt7