Question

A student weighing 700 N climbs at constant speed to the top of an 8 m vertical rope in 10 s. The average power expended by the student to overcome gravity is most nearly
1.1 W
87.5 W
560 W
875 W
5600 W

Answer 1

Answer:

The average power the student expended to overcome gravity is 560W, Watts is a units of work it is Joules /time or kg*$m^{2}$/ $s^{3}$

Explanation:

Weight = 700N

$F= m*g*h \\m*g= 700N\\F= 700N*h\\F=700N*8m\\F= 5600 N*m \\F=5600 J$

The power is the work in (Joules) or (N*m) in a determinate time (s) to get Watts (W) units for work

$Work= \frac{5600 J}{10s} = \frac{5600 \frac{kg*m^{2} }{s^{2} } }{10 s} \\Work= 560\frac{kg*m^{2} }{s^{3} } \\Work =560 W$