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Olenka [21]
3 years ago
9

You are on a new planet, and are trying to use a simple pendulum to find the gravity experienced on this new planet. You find th

at a pendulum having a length of 35 cm has a period of 2 seconds. What is the acceleration due to gravity on this planet?
A. 13.82 m/s^2
B. 345.4 m/s^2
C. 3.45 m/s^2
D. 1.1 m/s^2
Physics
1 answer:
levacccp [35]3 years ago
4 0

To solve this problem it is necessary to apply the concepts related to the Period based on the length of its rope and gravity, mathematically it can be expressed as

T= 2\pi \sqrt{\frac{L}{g}}

g = Gravity

L = Length

T = Period

Re-arrange to find the gravity we have

g = \frac{4\pi^2 L}{T^2}

Our values are given as

L = 0.35m\\T = 2s\\

Replacing we have

g = \frac{4\pi^2 L}{T^2}

g = \frac{4\pi^2 0.35}{2^2}

g = 3.45 m/s^2

Therefore the correct answer is C.

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kkurt [141]

Here as we know that there is no loss of energy

so we can say that maximum kinetic energy will become gravitational potential energy at its maximum height

So here we have

\frac{1}{2}mv^2 = mgh

here we have

v = 20 m/s

m = 8000 kg

now from above equation we have

\frac{1}{2}(8000)(20^2) = (8000)(9.8)h

h = \frac{200}{9.8)

h = 20.4 m

so maximum height is 20.4 m

4 0
3 years ago
Read 2 more answers
Two loudspeakers are placed next to each other and driven by the same source at 500 Hz. A listener is positioned in front of the
stellarik [79]

To solve this problem we will apply the concepts related to wavelength as the rate of change of the speed of the wave over the frequency. Mathematically this is

\lambda = \frac{v}{f}

Here,

v = Wave velocity

f = Frequency,

Replacing with our values we have that,

\lambda = \frac{340}{500}

\lambda = 0.68m

The distance to move one speaker is half this

\lambda/2 = 0.34m

Therefore the minimum distance will be 0.34m

7 0
3 years ago
If the 50 kg objects slows down to a velocity of 1 m/s how much kinetic energy does it have?
Bogdan [553]

It has 50kg with a velocity of 1 m/s times the speed of the cart divided by 2 and multiplied by kinectic x plus 5

3 0
3 years ago
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When will an object dropped from rest attain a speed of 30 m/s?
stich3 [128]
<h3><u>Answer</u> :</h3>

Initial velocity = zero (i.e., free fall)

Final velocity = 30m/s

Acceleration due to gravity = 10m/s²

For a body falling freely under the action of gravity, g is taken positive.

◈ <u>First equation of kinenatics</u> :

⇒ v = u + gt

⇒ 30 = 0 + 10t

⇒ t = 30/10

⇒ <u>t = 3s</u>

Hence, object will attain a speed of 30m/s after 3s.

8 0
3 years ago
A car accelerates along a straight road from rest to 90 km/h in 5.0 s. A) Find the magnitude of its average acceleration. B) Fin
egoroff_w [7]

Answer:

a)   A=5m/s^2

b)   V=25m/s

Explanation:

From the question we are told that:

Velocity v=90km/h=25m/s

Time t=5.0s

a)

Generally From Newton's motion equation for Average acceleration is   mathematically given by

  A=\frac{V-U}{t}

Since its from Rest Therefore

  U=0

 A=\frac{25m/s-0}{5s}

 A=5m/s^2

b)

Generally the equation for Average Velocity is mathematically given by

  V=u+at

 AT t=1.0s\\\\V=0+5(1)

 V=5m/s

 AT t=2.0s\\\\V=0+5(2)

 V=10m/s

 AT t=5.0s\\\\V=0+5(5)

 V=25m/s

 

6 0
2 years ago
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