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Olenka [21]
3 years ago
9

You are on a new planet, and are trying to use a simple pendulum to find the gravity experienced on this new planet. You find th

at a pendulum having a length of 35 cm has a period of 2 seconds. What is the acceleration due to gravity on this planet?
A. 13.82 m/s^2
B. 345.4 m/s^2
C. 3.45 m/s^2
D. 1.1 m/s^2
Physics
1 answer:
levacccp [35]3 years ago
4 0

To solve this problem it is necessary to apply the concepts related to the Period based on the length of its rope and gravity, mathematically it can be expressed as

T= 2\pi \sqrt{\frac{L}{g}}

g = Gravity

L = Length

T = Period

Re-arrange to find the gravity we have

g = \frac{4\pi^2 L}{T^2}

Our values are given as

L = 0.35m\\T = 2s\\

Replacing we have

g = \frac{4\pi^2 L}{T^2}

g = \frac{4\pi^2 0.35}{2^2}

g = 3.45 m/s^2

Therefore the correct answer is C.

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HELP: I’ve been stuck on this problem for a while now.
Arlecino [84]

Answer:

a.work done=force *displacement

=500N*46m

=23000 Joule

b.power=work done/time taken

=23000/25

=920 watt

c.GPE=m*g*h(m=mass,g=gravity due to acceleration,h=height)

=60kg*9.8m/s*14m

=8232 joule

Explanation:

3 0
3 years ago
Higher amplitudes sound will have a _____________________ sound while lower amplitude will have a __________________________ sou
lukranit [14]

Answer:

9)  HIGHER  AND LOWER INTESITY, 10) speed of sound must decrease.

11) guitar the strings, flute,  12) In the mountains,  13) sound of a low frequency horn (sub-wofeer)

     

Explanation:

In this exercise we are asked to complete the sentences.

9) the intensity of the sound is the square of the amplitude, the missing words are

      HIGHER INTESITY

      LOWER INTENSITY

10) the speed of sound is

          v = \sqrt{\frac{B}{\rho} }

and it is also related to temperature

         v = v_o \sqrt{1+ \frac{T}{273} }

We must be careful since the compressibility modulus (B) changes significantly between the solid, liquid and gaseous states, if we are in the same medium, the speed of sound decreases with increasing density. For a higher density the speed of sound decreases

Also the speed of sound increases with temperature, but its effect is less,

Therefore, by having these two effects in the opposite direction, the change in density is more important, so the speed of sound must decrease.

.

11) when you listen to a guitar the strings resonate with the instrument body

   on the flute has a resonance between the blown air and the flute tube

12) When you are in front of a tall object, the sound is reflected and the echo is heard.

      In the mountains, in the squares where there is a large object that reflects in sound

13) when we hear the sound of a low frequency horn (sub-wofeer) we feel the vibration of the air, this is an effect of the pressure energy of the sound on our chest

4 0
3 years ago
You drive 6.00 km at 50.0 km/h and then another 6.00kmat 900 km/h Your average speed over
Cerrena [4.2K]

Explanation:

average speed = total distance travelled / total time travelled

time to travel the first 6km: 6 / 50 = 3/25 (h)

time to travel the next 6km: 6 / 90 = 1/15 (h)

[I think there's problem in the question 'cause 900km/h sounds impossible for normal person to travel in normal condition]

The total time: 3/25 + 1/15 = 14/75 (h)

Average speed over the 12 km drive will be:

\frac{12}{ \frac{14}{75} }  =  \frac{450}{7}  = 64.3 \: km{h}^{ - 1}

8 0
3 years ago
An object moves in a circular path at a constant speed. what is the direction of the net force acting on the object?
mr Goodwill [35]
In a circular motion im pretty sure
6 0
3 years ago
A 0.280-kg croquet ball makes an elastic head-on collision with a second ball initially at rest. The second ball moves off with
Jet001 [13]

Answer:

mass of second ball is 0.84 kg

Explanation:

mass of ball = 0.280 kg

to find out

mass of the second ball

solution

we know here elastic head on collision and

second ball moves =  half the original speed

we consider here m1 mass of 1st ball and m2 mass of second ball

v1 = velocity of first ball before collision

v2 = velocity of second ball before collision

v3 = velocity of first ball after collision

v4 = velocity of second ball after collision

so here

we know 2nd ball was on rest so v2 = 0

after collision v4 = 1/2 ( v1)

and we know head on collision so

v3 = - v1/2

so from law of conservation of mass

m1v1 + m2v2 = m1v3 + m2v4

put here value

m1v1 + m2(0) = m1(-v1/2) + m2(v1/2)

solve and we get

m2 = 3m1

m2 = 3( 0.280) = 0.84

mass of second ball is 0.84 kg

7 0
4 years ago
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