The rate of change of velocity
Frequency = (speed) divided by (wavelength)
= (3 x 10⁸ m/s) / (700 x 10⁻⁹ m)
= (3 / 700) x 10¹⁷ ( per sec )
= 4.286 x 10¹⁴ per sec = 4.286 x 10¹⁴ Hz.
= 42,860 GHz .
Answer:
Acceleration, 
Explanation:
It is given that,
Initial speed of the aircraft, u = 140 mi/h = 62.58 m/s
Finally, it stops, v = 0
Time taken, t = 2 s
Let a is the acceleration of the aircraft. We know that the rate of change of velocity is called acceleration of the object. It is given by :



So, the acceleration of the aircraft is
and the car is decelerating. Hence, this is the required solution.
Answer:u=42.29 m/s
Explanation:
Given
Horizontal distance=167 m
launch angle
Let u be the initial speed of ball
Range



