Answer:
Time = 0.3256 sec
Explanation:
Velocity = displacement / time
43=14/t
So the time =14/43
t=0.3256 sec
Given:
rod of circular cross section is subjected to uniaxial tension.
Length, L=1500 mm
radius, r = 10 mm
E=2*10^5 N/mm^2
Force, F=20 kN = 20,000 N
[note: newton (unit) in abbreviation is written in upper case, as in N ]
From given above, area of cross section = π r^2 = 100 π =314 mm^2
(i) Stress,
σ
=force/area
= 20000 N / 314 mm^2
= 6366.2 N/mm^2
= 6370 N/mm^2 (to 3 significant figures)
(ii) Strain
ε
= ratio of extension / original length
= σ / E
= 6366.2 /(2*10^5)
= 0.03183
= 0.0318 (to three significant figures)
(iii) elongation
= ε * L
= 0.03183*1500 mm
= 47.746 mm
= 47.7 mm (to three significant figures)
I think the answer for the question above its b 1.2
True...<span>A moving </span>object<span> with a zero </span>resultant force<span> keeps moving at the same speed and in the same direction. If the </span>resultant force<span> acting on an </span>object<span> is not zero, a stationary </span>object<span> begins to </span>accelerate<span> in the same direction as the </span>force. A movingobject<span> speeds up, slows down or changes direction</span>