Answer:
they stay shifted the same amount to the red
Explanation:
Redshift is given by

Where,
= Wavelength observed
= Wavelength emitted
Also
Transverse redshift is given by

v = Velocity of object
c = Speed of light = 
So, if the velocity is constant the redshift remains the same
A silica-rich igneous rock that has large crystals and makes up much of the continental crust is called granite. These rocks are usually pink, gray or white in color depending on the minerals found on the rock. Generally, granite would have a range of 20% to 60% by volume of quartz and a minimum of 35% feldspar. This rock is a result from volcanic arcs and from the collision of continental masses. Due to its abundance, it has been used in a number of applications. It is used as an aggregate and filler in roading and construction industries. It is also cut and polished to be used in foyers, building facings, bench counters and tops.
Answer:
h = 3.1 cm
Explanation:
Given that,
The volume of a oil drop, V = 10 m
Radius, r = 10 m
We need to find the thickness of the film. The film is in the form of a cylinder whose volume is as follows :

So, the thickness of the film is equal to 3.1 cm.
I am not completely sure, but I believe that it depends on the total mass of the Protons and Neutrons
Answer:
is the time taken by the car to accelerate the desired range of the speed from zero at full power.
Explanation:
Given:
Range of speed during which constant power is supplied to the wheels by the car is
.
- Initial velocity of the car,

- final velocity of the car during the test,

- Time taken to accelerate form zero to 32 mph at full power,

- initial velocity of the car,

- final desired velocity of the car,

Now the acceleration of the car:



Now using the equation of motion:


is the time taken by the car to accelerate the desired range of the speed from zero at full power.