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olga55 [171]
2 years ago
5

What features were the last to form on the moon?

Physics
2 answers:
snow_lady [41]2 years ago
8 0

Answer:

Rays

Explanation:

The moon was formed about 4.5 billion years ago according to most accepted Giant-impact theory. The Lunar surface has shows the following surface features:

<u>Mares</u>-The dark areas of the moon are filled with lava. These smooth and large areas can be seen from the Earth as well. These are about 3 billion years old.

<u>Crater-</u> These are formed when meteoroid impacts the surface. A depression is formed. Thousands of depressions are present of moon's surface. Lundar surface is continuously bombarded by the small meteors. The largest crater is the Tycho crater.

<u>Mountains and ranges-</u> are the bumps on the surface of the moon. These were formed about 4 billion years ago.

<u>Rills-</u> the cracks present on the lunar surface due to motion of its surface.

<u>Rays- </u>these features were last to form. These are bright rays - streaks of debris which radiate out from large impact craters.

kap26 [50]2 years ago
3 0
<span>Rayed craters-</span><span> were the last features to form on the moon.</span>
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Calculate the electric field at one corner of a square 50 cm on a side if the other corners are occupied by 250x10-7C (charges)
SIZIF [17.4K]

The electric field at one corner of a square is 1614217 N/C.

Explanation:

The distance between x and y direction diagonals.

As per the given details the distance between diagonals is calculated as

0.5² + 0.5² = c²  =>  c = 0.707 m

Charge to the right:  In x direction

In order to find the electric charge towards x direction

we use e = kq/r² formula

As 'k' is coulomb's constant it's value is 9 x 10^{9} N m²/C²

e = (9 x 10^{9})(250 x 10^{-7}) / (0.5)²

e = 9 x 10^{5} N/C

Charge diagonal:

e = kq/r²

e = [(9 x 10^{9})(250 x 10^{-7}) / (0.707)²] cos 45

e = 225000√2 N/C

X direction sum = 1218198 N/C.

Similarly as shown in x direction the charge is same for y direction also

Charge below:  For y direction

e = kq/r²

e = (9 x 10^{9})(250 x 10^{-7}) / (0.5)²

e = 9 x 10^{5} N/C

Charge diagonal:

e = kq/r²

e = [(9 x 10^{9})(250 x 10^{-7}) / (0.5)²] sin 45

e = 159099 N/C

Y direction sum = 1059099 N/C

Resultant electric field strength:

1218198 ² + 1059099² = e²

e = 1614217 N/C [45 degrees below the horizontal]

4 0
3 years ago
What are two ways an engineer can build a car in order for it to accelerate faster
Ket [755]

Explanation:

Take F=ma

a = F/m

For a higher, F higher or m lower

Means higher horse power for engine or lower mass for the car

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Shkiper50 [21]

Answer:

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I really hate the runaround

You really got me paranoid

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2 years ago
Charlie Brown kicks a football at 24.5 m/s at 35.0. What is the maximum height of the ball?
lozanna [386]

Answer:

d = 10.076 m

Explanation:

We need to obtain the velocity of the ball in the y direction

Vy  = 24.5m/s * sin(35) = 14.053 m/s

To obtain the distance, we use the formula

vf^2 = v0^2 -2*g*d

but vf = 0

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