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3 years ago

What is the molarity of solution that is 5.50 percentage by mass oxalic acid and has a density of 1.024 g/ml

Chemistry

1 answer:

Y_Kistochka [10]3 years ago

6 0

Answer:

0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.

Explanation:

Mass percentage of oxalic acid = 5.50%

This means that in 100 grams of solution there are 5.50 grams of oxalic acid.

Mass of solution , m = 100

Volume of the solution = V

Density of the solution = d = 1.024 g/mL

$V=\frac{m}{d}=\frac{100 g}{1.024 g/mL}=97.66mL$

V = 97.66 mL = 0.09766 L

(1 mL = 0.001 L)

Moles of oxalic acid = $\frac{5.50 g}{90 g/mol}=0.06111 mol$

$Molarity=\frac{\text{Moles of solute}}{\text{Volume of solution in L}}$

The molarity of the solution :

$=\frac{0.06111 mol}{0.09766 L}=0.6257M$

0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.

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T: temperature in Kelvin (25 + 273 = 298 K)

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And moles can be calculated using this expression:

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Replacing (3) in (2), and then in (1) we have:

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Now, we just need to replace the given data into the above expression to get the value of the molecular mass:

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