Question

What is the molarity of solution that is 5.50 percentage by mass oxalic acid and has a density of 1.024 g/ml

Answer 1

Answer:

0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.

Explanation:

Mass percentage of oxalic acid = 5.50%

This means that in 100 grams of solution there are 5.50 grams of oxalic acid.

Mass of solution , m = 100

Volume of the solution = V

Density of the solution = d = 1.024 g/mL

$V=\frac{m}{d}=\frac{100 g}{1.024 g/mL}=97.66mL$

V = 97.66 mL = 0.09766 L

(1 mL = 0.001 L)

Moles of oxalic acid = $\frac{5.50 g}{90 g/mol}=0.06111 mol$

$Molarity=\frac{\text{Moles of solute}}{\text{Volume of solution in L}}$

The molarity of the solution :

$=\frac{0.06111 mol}{0.09766 L}=0.6257M$

0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.