Hey There!:
Molar Mass KI => 166.003 g/mol
* number of moles:
n = mass of solute / molar mass
n = 49.8 / 166.003
n = 0.3 moles KI
Therefore:
M = n / V
M = 0.3 / 1.00
M = 0.3 mol/L
hope this helps!
Filling out the table below following the outlined order:
- Calcium - symbol = Ca; Group =2; Period = 4; Ar = 134; Am =40.078u; Ph = solid; Density = 1.55; Bp = 1757K; Mp = 1115K.
- Vanadium - symbol = V; Group =5; Period = 4; Ar = 197; Am =50.9415u; Ph = solid; Density = 6.11; Bp = 3680K; Mp = 2183K.
- Manganese - symbol = Mn; Group =7; Period = 4; Ar = 127; Am = 54.938044u; Ph = solid; Density = 7.21; Bp = 2334K; Mp = 1519K.
- Cobalt: - symbol = Co; Group =9; Period = 4; Ar = 125; Am =58.933195 u; Ph = solid; Density = 8.90; Bp = 3200K; Mp = 1768K.
- Zinc: - symbol = Zn; Group = 12; Period = 4; Ar = 134; Am =65.38 u; Ph = solid; Density = 7.14; Bp = 1180K; Mp = 692.68K.
- Arsenic: - symbol = As; Group = 15; Period = 4; Ar = 197; Am = 74.9216 u; Ph = solid; Density = 5.75; Bp = 889K; Mp = 889K.
- Bromine: - symbol = Br; Group =17; Period = 4; Ar = 120; Am = 79.904 u; Ph = Liquid; Density = 3.1028; Bp = 332K; Mp = 265K.
<h3>Meaning of Element</h3>
An element can be defined as a substance that can not be broken down into simpler substances.
An element serves as a building blocks for compounds and mixtures.
In conclusion, each element and its property as requested in the table are given above.
Learn more about element : brainly.com/question/18096867
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Answer: A, parrots eat seeds, fruit, and nuts, while hawks eat meat.
Explanation:
This option is more onto the behavioral and what the parrots did, while the other options were more on the parrots physical attributions.
<em>I hope this helped! :)</em>
Answer:
C:to the right side of the periodic table, and it is given
the suffix -ide.
Answer:
5.0 x 10⁹ years.
Explanation:
- It is known that the decay of a radioactive isotope isotope obeys first order kinetics.
- Half-life time is the time needed for the reactants to be in its half concentration.
- If reactant has initial concentration [A₀], after half-life time its concentration will be ([A₀]/2).
- Also, it is clear that in first order decay the half-life time is independent of the initial concentration.
- The half-life of K-40 = 1.251 × 10⁹ years.
- For, first order reactions:
<em>k = ln(2)/(t1/2) = 0.693/(t1/2).</em>
Where, k is the rate constant of the reaction.
t1/2 is the half-life of the reaction.
∴ k =0.693/(t1/2) = 0.693/(1.251 × 10⁹ years) = 5.54 x 10⁻¹⁰ year⁻¹.
- Also, we have the integral law of first order reaction:
<em>kt = ln([A₀]/[A]),</em>
where, k is the rate constant of the reaction (k = 5.54 x 10⁻¹⁰ year⁻¹).
t is the time of the reaction (t = ??? year).
[A₀] is the initial concentration of (K-40) ([A₀] = 100%).
[A] is the remaining concentration of (K-40) ([A] = 6.25%).
∴ (5.54 x 10⁻¹⁰ year⁻¹)(t) = ln((100%)/( 6.25%))
∴ (5.54 x 10⁻¹⁰ year⁻¹)(t) = 2.77.
∴ t = 2.77/(5.54 x 10⁻¹⁰ year⁻¹) = 5.0 x 10⁹ years.
