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Oksana_A [137]
3 years ago
11

(FLUID MECHANICS)

Physics
1 answer:
Vera_Pavlovna [14]3 years ago
3 0

Answer:

option B

Explanation:

When a body is immersed in liquid there will be two force is acting on the body.

First one force acting downward due to weight of the body.

And the second force acting on the object will be buoyant force.

If the object is not in equilibrium the apparent weight will be equal to net force acting on the object.

     F_{net} = W - F_b

W is the weight of the object acting downward

Fb is the buoyancy force acting upward on the object.

Hence, the correct answer is option B

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A fatigue test was conducted in which the mean stress was 50 MPa (7250 psi) and the stress amplitude was 225 MPa (32,625 psi).
Tems11 [23]

Answer:

275 MPa, -175 MPa

-0.63636

450 MPa

Explanation:

\sigma_{max} = Maximum stress

\sigma_{min} = Minimum stress

\sigma_m = Mean stress = 50 MPa

\sigma_a = Stress amplitude = 225 MPa

Mean stress is given by

\sigma_m=\frac{\sigma_{max}+\sigma_{min}}{2}\\\Rightarrow \sigma_{max}+\sigma_{min}=2\sigma_m\\\Rightarrow \sigma_{max}+\sigma_{min}=2\times 50\\\Rightarrow \sigma_{max}+\sigma_{min}=100\ MPa\\\Rightarrow \sigma_{max}=100-\sigma_{min}

Stress amplitude is given by

\sigma_a=\frac{\sigma_{max}-\sigma_{min}}{2}\\\Rightarrow \sigma_{max}-\sigma_{min}=2\sigma_a\\\Rightarrow \sigma_{max}-\sigma_{min}=2\times 225\\\Rightarrow \sigma_{max}-\sigma_{min}=450\ MPa\\\Rightarrow 100-\sigma_{min}-\sigma_{min}=450\\\Rightarrow -2\sigma_{min}=350\\\Rightarrow \sigma_{min}=-175\ MPa

\sigma_{max}=100-\sigma_{min}\\\Rightarrow \sigma_{max}=100-(-175)\\\Rightarrow \sigma_{max}=275\ MPa

Maximum stress level is 275 MPa

Minimum stress level is -175 MPa

Stress ratio is given by

R=\frac{\sigma_{min}}{\sigma_{max}}\\\Rightarrow R=\frac{-175}{275}\\\Rightarrow R=-0.63636

The stress ratio is -0.63636

Stress range is given by

\sigma_{max}-\sigma_{min}=450\ MPa

Magnitude of the stress range is 450 MPa

8 0
3 years ago
No file link please
musickatia [10]
Rock 3, because it has the most mass while still moving at the same speed, it is kinetic because there is movement and energy being used
5 0
3 years ago
A lunar module weighs 12 metric tons on the surface of the Earth. How much work is done in propelling the module from the surfac
zhuklara [117]

Answer:

W=76.55 miles.metric tons

Explanation:

Given that

Weight on the earth = 12 tons

So weight on the moon =12/6 = 2 tons

 ( because at moon g will become g/6)

As we know that

F=\dfrac{K}{x^2}

Here x= 1100 miles

F 2 tons

2=\dfrac{K}{1100^2}

So

K=2.4\times 10^6

We know that

Work = F. dx

W=\int_{x_1}^{x_2}F.dx

W=\int_{1100}^{1140}\dfrac{2.4\times 10^6}{x^2}.dx

W=-2.4\times 10^6\left[\dfrac{1}{x}\right]_{1100}^{1140}

W=-2.4\times 10^6\left[\dfrac{1}{1140}-\dfrac{1}{1100}\right]

W=76.55 miles.metric tons

6 0
3 years ago
A sinusoidal traveling wave is generated on a string by an oscillating source that completes 116 cycles per minute. What is the
slava [35]

Answer:

\lambda =6.32\ cm

Explanation:

given,

number of cycle complete (f) = 116 cycles per minute

wavelength observed at 11 m in 1.5 m.

v = \dfrac{distance}{time}

v = \dfrac{11}{1.5}

v = 7.33 m/s

\lambda = \dfrac{v}{f}

\lambda = \dfrac{7.33}{116}

\lambda =0.0632\ m

\lambda =6.32\ cm

The wavelength of the wave is equal to \lambda =6.32\ cm

6 0
3 years ago
A car travelling at a constant speed of 70km/h passes a stationary police car. The police car immediately goes on the chase acce
Virty [35]

Answer:

18.24 seconds

Explanation:

First you convert the km/h to m/s, 70km/h=(175/9)m/s,85km/h=(425/18)m/s.

You know it took 10 seconds for the police to reach 85 km/h. Calculate the distance that the car is ahead of the police (175/9)*10=1750/9m. Then by divide 1750/9 with 425/18, you will get the value 8.24. Add the 10 seconds with the 8.24 you will get 18.24 sec which is the total time.

5 0
4 years ago
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