Answer:
Decomposition.
Explanation:
Decomposition Reactions T hose reactions in which a single substance (reactant) splits up into two or more simpler substances (products) are known as decomposition reactions. These reactions are carried out by supplying energy in form of heat, electricity or light which breaks that substance into simpler substances
Answer:
The answer to your question is: c
Explanation:
A descomposition reaction is a chemical reaction in which the only one reactant yields two or more products.
a) HCl + NaHCO3 → H2O + CO2 + NaCl
This is not a descomposition reaction because there are two reactants not one, this option is incorrect.
b) 2Na + Cl2 → 2NaCl
THis option is also incorrect because there are two reactants in descompositin reaction there is only one reactant.
c) 2HgO → 2Hg + O2
There are only one reactant that yields 2 products, this is a descomposition reaction.
d) AgNO3 + NaCl → AgCl + NaNO3
THis is not a descomposition reaction because there are two reactants.
Answer:
covalent bond
Explanation:
A carbon–oxygen bond is a polar covalent bond between carbon and oxygen. Oxygen has 6 valence electrons and prefers to either share two electrons in bonding with carbon, leaving the 4 nonbonding electrons in 2 lone pairs :O: or to share two pairs of electrons to form the carbonyl functional group.
There are three major steps for finding an empirical formula from a combustion reaction.
1.) Determine the grams of carbon and hydrogen from the given data.
C: 23.98 g x (12.011 g / 44.01 g) = 6.54 g C
H: 4.91 g x (2.0158 g / 18.02 g) = 0.55 g H
Determine the grams of oxygen in the sample by subtracting the mass of the compound given from the total mass solved earlier.
O: 10.0 - (6.54 + 0.55) = 2.91 g O
2) Convert the values in step 1 to moles.
C: 6.54 g / 12.01 g / mol = 0.54 mol
H: 0.55 g / 1.01 g/mol = 0.54 mol
O: 2.91 g / 16.00 g/mol = 0.18 mol
3) Divide each by the lowest value calculated in step 2
C: 0.54 mol / 0.18 mol = 3
H: 0.54 mol / 0.18 mol = 3
O: 0.18 mol / 0.18 mol = 1
Thus, the empirical formula is C3H3O.