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Shkiper50 [21]
3 years ago
8

Select the example that best describes a renewable resource.

Physics
2 answers:
Strike441 [17]3 years ago
4 0

b. B. In some areas, heat from deep in the Earth can be used to heat water and homes.

densk [106]3 years ago
3 0
B. "In some areas, heat from deep in the Earth can be used to hear water and homes". Because the heat is never ending and isn't known to slowly deprive.
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How does an object move when it is subject to a steady centripetal force
LiRa [457]
Then the object moves in a circle.
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The moon is slowly moving away from the earth. What will eventually happen to the gravitational pull force between the earth and
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The gravitational pull will reduce, because the moon is moving further away from the centre of the earth. In other words, the further an object is from the centre of the earth, the weaker the gravitational pull that will be exerted on it. 
6 0
3 years ago
A singly charged positive ion has a mass of 3.46 × 10−26 kg. After being accelerated through a potential difference of 215 V the
jasenka [17]

Answer:

1.8 cm

Explanation:

m = mass of the singly charged positive ion = 3.46 x 10⁻²⁶ kg

q = charge on the singly charged positive ion = 1.6 x 10⁻¹⁹ C

\Delta V =Potential difference through which the ion is accelerated = 215 V

v = Speed of the ion

Using conservation of energy

Kinetic energy gained by ion = Electric potential energy lost

(0.5) m v^{2} = q \Delta V\\(0.5) (3.46\times10^{-26}) v^{2} = (1.6\times10^{-19}) (215)\\(1.73\times10^{-26}) v^{2} = 344\times10^{-19}\\v = 4.5\times10^{4} ms^{-1}

r = Radius of the path followed by ion

B = Magnitude of magnetic field = 0.522 T

the magnetic force on the ion provides the necessary centripetal force, hence

qvB = \frac{mv^{2} }{r} \\qB = \frac{mv}{r}\\r =\frac{mv}{qB}\\r =\frac{(3.46\times10^{-26})(4.5\times10^{4})}{(1.6\times10^{-19})(0.522)}\\r = 0.018 m \\r = 1.8 cm

5 0
3 years ago
If you want to conduct an electrical current, which situation would produce a solution capable of this? A) Dissolving water in o
svp [43]
D dissolving solid NaF in water

6 0
3 years ago
Read 2 more answers
Electrons (mass m, charge –e) are accelerated from rest through a potential difference V and are then deflected by a magnetic fi
adell [148]

Answer:

r=\dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}

Explanation:

Let m and e are the mass and charge of an electron. It is accelerated from rest through a potential difference V and are then deflected by a magnetic field that is perpendicular to their velocity. Let v is the velocity of the electron. It can be calculated as :

\dfrac{1}{2}mv^2=eV

v=\sqrt{\dfrac{2eV}{m}}

When the electron enters the magnetic field, the centripetal force is balanced by the magnetic force as :

\dfrac{mv^2}{r}=evB

r=\dfrac{mv}{eB}

or

r=\dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}

So, the radius of the resulting electron trajectory is \dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}. Hence, this is the required solution.

8 0
3 years ago
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