This would be called elevation
Answer:
J = 500 kg-m/s
Explanation:
Given that,
Initial speed of the motor, u = 5 m/s
Final speed of the motor, v = 7 m/s
Mass of the boat, m = 250 kg
We need to find the impulse applied by the motor. We know that impulse is equal to the change in momentum. It is represented by letter J.
J = m(v-u)
J = 250 (7-5)
J = 500 kg-m/s
Hence, the impulse applied by the motor is 500 kg-m/s.
Formula :
K = 273.15 + C
40°C
K= 273,15 +40°
K= 313,15 °
40 degrees Celsius = 313.15 kelvin
Answer:
Three other length for which resonance will occur is 66 cm, 110 cm and 154 cm
Explanation:
As we know that the length of the pipe is 22 cm
Now let say it is in 1st harmonic state so we have
so we have
So we have
For N = 1
For N = 2
For N = 3
Answer:
Distance between them increase
Explanation:
The position S of the water droplet can be determined using equation of motion
where is the initial velocity which is zero here
is time taken, is acceleration due to gravity
the position of first drop after time is given by
the position of next drop at same time is
distance between them is is
from the above the difference will increase with the time