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romanna [79]
3 years ago
13

La masa de un objeto en la tierra es de 100 kg.

Physics
1 answer:
andreev551 [17]3 years ago
3 0

Answer:

a) 980 N

b) 100 kg

c)  163.33 N

Explanation:

a)

The weight of the object on Earth is the product of its mass times the acceleration due to gravity, that is:

W=m\,g=(100\,\,kg)\,g=(100\,\,kg)\,(9.8\,\,m/s^2)=980\,\,N

b)

The mass of the object on the moon, is exactly the same (100 kg) since mass is an inherited value of the object.

c)

Considering that the acceleration of gravity on the Moon is about 1/6 that we have on earth (g), then the weight of the object on the Moon becomes:

W=m\,\frac{g}{6} =\frac{980}{6}\,\,N=163.33\,\,N

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A 35-mm single lens reflex (SLR) digital camera is using a lens of focal length 35.0 mm to photograph a person who is 1.80 m tal
olganol [36]

Answer:

a) 35.44 mm

b) 17.67 mm

Explanation:

u = Object distance =  3.6 m

v = Image distance

f = Focal length = 35 mm

h_u= Object height = 1.8 m

a) Lens Equation

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{35}-\frac{1}{3600}\\\Rightarrow \frac{1}{v}=\frac{713}{25200} \\\Rightarrow v=\frac{25200}{713}=35.34\ mm

The CCD sensor is 35.34 mm from the lens

b) Magnification

m=-\frac{v}{u}\\\Rightarrow m=-\frac{35.34}{3600}

m=\frac{h_v}{h_u}\\\Rightarrow -\frac{35.34}{3600}=\frac{h_v}{1800}\\\Rightarrow h_v=-\frac{35.34}{3600}\times 1800=-17.67\ mm

The person appears 17.67 mm tall on the sensor

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