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3 years ago

What mass of water would be produced if 1.5 g of ethanoic acid was reacted completely with sodium hydroxide (3 marks)

Chemistry

1 answer:

Zigmanuir [339]3 years ago

5 0

Mass of water : 0.45 g

<h3>Further explanation</h3>

Given

1.5 g ethanoic acid

Required

Mass of water

Solution

Reaction

<em>CH₃COOH + NaOH ⇒H₂O + CH₃COONa</em>

mol CH₃COOH(MW=60 g/mol) :

= mass : MW

= 1.5 : 60

= 0.025

mol H₂O from the equation :

= 0.025(mol ratio CH₃COOH : H₂O= 1 : 1)

Mass of water :

= mol x MW water

= 0.025 x 18 g/mol

= 0.45 g

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How much energy (heat) is required to convert 248 g of water from 0 oC to 154 oC? Assume that the water begins as a liquid, that

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The total heat required is 691,026.36 J

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Latent heat is the amount of heat that a body receives or gives to produce a phase change. It is calculated as: Q = m. L

Where Q: amount of heat, m: mass and L: latent heat

On the other hand, sensible heat is the amount of heat that a body can receive or give up due to a change in temperature. Its calculation is through the expression:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the change in temperature (Tfinal - Tinitial).

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Q for liquid water. This is, raise 248 g of liquid water from O to 100 Celsius. So you calculate the sensible heat of water from temperature 0 °C to 100° C

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$Q=4.184\frac{J}{g*C} *248 g* (100 -0 )C$

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Q for temperature change from 100.0 ∘ C to 154 ∘ C, this is, the sensible heat of steam from 100 °C to 154°C.

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Q=25,176.96 J

So, total heat= 103,763.2 J + 562,086.2 J + 25,176.96 J= 691,026.36 J

<u><em>The total heat required is 691,026.36 J</em></u>

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