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3 years ago

A drag-racing car goes fro 0 to 300mph in 5 seconds. What is its average acceleration in g's?

1 answer:

8 0

I think that the short answer to this question is to convert 300mph into metres per second, and then divide by 5 to get the average acceleration. Since 1g is, I think, 9.81 m/s^2 (nearly 10), dividing by 9.81 should give the number of gs in the acceleration.1 mile is 1760 yards which is 1760x3 feet which is 1760x3x12 inches.300 miles would be 300x1760x3x12 inches.1 inch is 2.54 cm.300 miles would be 2.54x300x1760x3x12 cm.300 miles would be 2.54x300x1760x3x12/100 m.Then do the number of seconds in an hour.I hope this helps ...

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In a chemical equation, the chemicals that react are considered . In a chemical equation, the chemicals that are produced are co

vovangra [49]

Answer

Hi,

In a chemical equation, chemicals that react are the reactants, while chemicals that are produced are the products/by products. Both sides of the equation must be balanced.

Explanation

When writing a chemical equation, reactants reacts to produce products. For example in the equation for formation of water, hydrogen combines with oxygen as 2H₂ +O₂→2H₂O where the first part before the arrow represent the reactants and the next part after the arrow are the products. Reactants are on the left where as products are on the right.Coefficient 2, in this cases is used for balancing the equation.

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4 0

3 years ago

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A circuit has a 10 Ω resistor connected to a 1.5 V dry cell. What is the current that can flow in the circuit?

ludmilkaskok [199]

Here is the highly detailed, arcane, complex, technical form of Ohm's Law that is needed in order to answer this question ===> I = V / R .

Current = (voltage) / (resistance)

Current = (1.5 V) / (10 Ω)

<em>Current = 0.15 Ampere</em>

8 0

3 years ago

A car traveling on a flat (unbanked) circular track accelerates uniformly from rest with a tangential acceleration of 1.7 m/s^2.

Komok [63]

Answer:

The coefficient of static friction between the car and the track

u=0.572

Explanation:

We don't know the mass of the car or any other information so the acceleration is the reason to solve the friction coefficient

∑ $F=F_{f}=m*a_{t}$

As we know

$F_{f}=u*F_{N}=u*m*g$

Also the center ward direction forces

$F_{fc}=m*a_{c}$

$a_{c}=\frac{v_{t}^2}{r}$

$F_{fc}=m*\frac{v_{t}^2}{r}$

But now vt relation with the tangential acceleration

$v_{t}=2*a_{t}*\frac{\pi }{r}$

replacing

$F_{fc}=m*a_{t}*\frac{2\pi*r}{2r}$

$F_{fc}=m*a_{t}*\pi$

So magnitude of the force can get by

$F_{f}=\sqrt{(m*a_{t}*\pi)^{2}+(m*a_{t})^{2}}$

Get the factor to simplify

$F_{f}=a_{t}*m*\sqrt{(1+\pi^2)}$

$u*m*g=m*a_{t}*(\sqrt{1+\pi^2})$

Solve to u'

$u=\frac{a_{t}}{g}*(\sqrt{1+\pi^2})$

$u=\frac{17\frac{m}{s^2} }{9.8\frac{m}{s^2}}*(\sqrt{1+\pi^2})=0.572$

5 0

3 years ago

What are the three properties of a magnet?

Mamont248 [21]

1. Magnets attract iron and other ferromagnetic materials such as neodymium and cobalt.

2. Magnets attract or repel other magnets.

3. In addition one part of a magnet will always point north when allowed to swing freely.

8 0

3 years ago

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A naval engineer is testing an nonreflective coating for submarines that would help them avoid detection by producing destructiv

borishaifa [10]

Answer:

5 cm .

Explanation:

Wave length of sonar waves λ = 1390 / 512

= 2.715 m

For waves getting reflected from both layers of the coating , undergoing phase reversal , net change will be zero .

For destructive interference

path diff = ( 2n+1) λ / 2

2μt = ( 2n+1) λ / 2

2 x 13.5 x t = ( 2n+1) λ / 2

for minimum thickness

n = 0

2 x 13.5 x t = λ / 2

t = λ / (2 x 27)

= 2.715 / 2 x 27

= .05 m

5 cm .

3 0

3 years ago