F=G(m1*m2)\D^2
so
G=6.67 × 10^(-11)<span> m</span>3<span> kg</span>-1<span> s</span><span>-2
</span>
= G(2*2)\4
=G
Answer:
a)F=(208 i+156 j) kN
b)F+W=219 kN
Explanation:
Solution:
To determine the components of F
F=(260 kN).(
)
=(208 i+156 j) kN
F=(208 i+156 j) kN
b)weight W expressed in component and add into the
Force F.
W=-(8800 kg).(9.81 m/s^2)j
F+W=(208 i+[156-86.3]j) kN
F+W=
=219 kN
F+W=219 kN
Answer:
5.03×10¯⁷ N
Explanation:
From the question given above, the following data were obtained:
Mass of the person (M₁) = 55 Kg
Mass of the car (M₂) = 1234 Kg
Distance apart (r) = 3 m
Gravitational constant (G) = 6.673×10¯¹¹ Nm²/Kg²
Force (F) =?
The force between the person and his car can be obtained as follow:
F = GM₁M₂ / r²
F = 6.673×10¯¹¹ × 55 × 1234 / 3²
F = 6.673×10¯¹¹ × 67870/ 9
F = 5.03×10¯⁷ N
Thus, the force between the person and his car is 5.03×10¯⁷ N
the car will move but you will not move in tell you are acted on by a force Newton's laws of motion
