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3 years ago

Which statement is true about gravitational forces?

2 answers:

6 0

Hey there!

Your correct answer would be (<span>Every mass exerts a gravitational force on every other mass.) It really doesn't matter the size in mass what so ever, gravity is stronger than mass, mass in nothing compared to mass. Therefor, gravity exert's mass on any object with any size of mass.

Your correct answer would be . . .

</span> $\boxed{\boxed{Every \ mass \ exerts \ a \ gravitational \ force \ on \ every \ other \ mass}}$
<span>
Hope this helps.
~Jurgen</span>

Helen [10]3 years ago

6 0

Answer:

C. Every mass exerts a gravitational force on every other mass.

Explanation:

Gravitational force is one of the four fundamental forces of nature. It is the force that binds together all the object in the universe. This force is exerted by all the object having mass on another objects having mass. It doesn't matter whether the mass is less or more. With change in mass the amount of force will vary but the gravitational force will still be acting on everything having mass.

The gravitational force between two objects of mass m₁ and m₂ separated by a distance r is given as:

$F = \frac{G\times m_{1}\times m_{2}}{r^{2}}$

G = Universal gravitational constant

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Light is reflected from a crystal of table salt with an index of refraction of 1.544. An analyser is placed to intercept the ref

Vitek1552 [10]

Answer:

hola me llamo bruno y tu?

Explanation:

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5 0

3 years ago

Describe what long sight is and how it is corrected with a lens

o-na [289]

If long sight means farsighted, then here's your answer:

Farsightedness is when the lens has difficulty focusing on nearby objects. Sufferers must squint to see the nearby objects. Reading, writing, and drawing for longer periods of time can cause eyestrain and headache.

Being farsighted can be corrected with prescription glasses or contact lenses or surgery.

7 0

4 years ago

A 25 kg circular disk has a diameter of 2.5 feet and a thickness of 2.5 cm. Find the density of the disk in kg/m3. Next, find th

Gre4nikov [31]

Answer:

Assume that $\rm g= 9.81\; N\cdot kg^{-1}$ ; $\rho(\text{Water}) = \rm 1000\;kg\cdot m^{-3}$ .

Density of the disk: approximately $\rm 2.19\times 10^{3}\; kg\cdot m^{-3}$ .

Weight of the disk: approximately $\rm 245\;N$ .

Buoyant force on the disk if it is submerged under water: approximately $\rm 112\; N$ .

The disk will sink when placed in water.

Explanation:

Convert the dimensions of this disk to SI units:

Diameter: $d = \rm 25\; inches = (25\times 0.3048)\; m = 0.762\;m$ .
Thickness $h = \rm 2.5\; cm = (2.5\times 0.01)\; m = 0.025\;m$ .

The radius of a circle is 1/2 its diameter:

$\displaystyle r = \rm \frac{1}{2}\times 0.762\;m = 0.381\; m$ .

Volume of this disk:

$V(\text{disk}) = \pi\cdot r^{2}\cdot h = \pi\times 0.381^{2}\times 0.025 \approx 0.0114009\; m^{3}$ .

Density of this disk:

$\displaystyle \rho(\text{disk}) = \frac{m}{V} = \rm \frac{25\; kg}{0.0114009\; m^{3}} = 2.19\times 10^{3}\;kg\cdot m^{-3}$ .

$\rho(\text{disk}) >\rho(\text{water})$ indicates that the disk will sink when placed in water.

Weight of the object:

$W(\text{disk}) = m\cdot g = \rm 25\times 9.81 = 245.25\; N$ .

The buoyant force on an object in water is equal to the weight of water that this object displaces. When this disk is submerged under water, it will displace approximately $\rm 0.0114009\; m^{3}$ of water. The buoyant force on the disk will be:

$\begin{aligned}F(\text{buoyant force}) &= W(\text{Water Displaced}) \\& = \rho\cdot V(\text{Water Displaced})\cdot g\\ & = \rm 1\times 10^{3}\; kg\cdot m^{-3}\times 0.0114009\; m^{3}\times 9.81\; N\cdot kg^{-1}\\ &\approx \rm 112\; N\end{aligned}$ .

The size of this disk's weight is greater than the size of the buoyant force on it when submerged under water. As a result, the disk will sink when placed in water.

3 0

3 years ago

Hoop rolling up an inclined plane A hollow cylinder (or hoop) is rolling along a horizontal surface with speed v = 3.3 m/s when

Naya [18.7K]

Answer:

Explanation:

For rolling up or down an incline plane , the acceleration or deceleration of the rolling body is given by the following expression

a = g sinθ / (1 + k²/r² )

where k is radius of gyration of rolling body and θ is angle of inclination

a = g sin15 / ( 1 + 1 ) [ for hoop k = r ]

a = 9.8 x .2588 / 2

= 1.268 m / s²

a )

Let s be the distance up to which it goes

v² = u² - 2as

0 = 3.3² - 2 x 1.268 s

s = 4.3 m

b ) Let time in going up be t₁

v = u - at₁

0 = 3.3 - 1.268 t₁

t₁ = 2.6 s

Time in going down t₂

s = 1/2 a t₂²

4.3 = .5 x 1.268 t₂²

t₂ = 2.60

Total time

= t₁ +t₂

= 2.6 + 2.6

= 5.2 s

4 0

4 years ago

A soap bubble, when illuminated with light of frequency 5.27 Hz × 1014 Hz, appears to be especially reflective. If it is surroun

denis23 [38]

Answer:

$1.07004\times 10^{-7}\ m$

Explanation:

$n_s$ = Refractive index of bubble = 1.33

f = Frequency of light = $5.27\times 10^{14}\ Hz$

c = Speed of light = $3\times 10^8\ m/s$

The wavelength of light is given by

$\lambda=\dfrac{2n_st}{m-\dfrac{1}{2}}$

Wavelength is also given by

$\lambda=\dfrac{c}{f}$

m = 1 for minimum thickness

$\dfrac{c}{f}=\dfrac{2n_st}{m-\dfrac{1}{2}}\\\Rightarrow t=\dfrac{m-\dfrac{1}{2}c}{2n_sf}\\\Rightarrow t=\dfrac{(1-\dfrac{1}{2})\times 3\times 10^8}{2\times 1.33\times 5.27\times 10^{14}}\\\Rightarrow t=1.07004\times 10^{-7}\ m$

The minimum thickness is $1.07004\times 10^{-7}\ m$

4 0

3 years ago