Question

The missile s engine exerts a 260-kN force F.

Answer 1

Answer:

a)F=(208 i+156 j) kN

b)F+W=219 kN

Explanation:

Solution:

To determine the components of F

F=(260 kN).($\frac{4}{\sqrt{4^{2}+3^{2}}}i+\frac{3}{\sqrt{4^{2}+3^{2}}}j$)

 =(208 i+156 j) kN

F=(208 i+156 j) kN

b)weight W expressed in component and add into the    

   Force F.

W=-(8800 kg).(9.81 m/s^2)j

F+W=(208 i+[156-86.3]j) kN

F+W=$\sqrt{(208kN)^{2}+(-69.7kN)^{2} }$

         =219 kN

F+W=219 kN