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3 years ago

Which of the following expressions is equivalent to the expression

Physics

1 answer:

Olin [163]3 years ago

5 0

Answer:

B. 50/-8

Explanation:

The expression -50/8 is equivalent to;

-50/8 = -6.25

The expression; 50/-8 is also equal to -6.25

Therefore;

The expression; -50/8 is equal to 50/-8

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if the displacement of a body is proportional to the square of time, state the nature of motion of the body

Liula [17]

Explanation:

If the displacement of an object is proportional to the square of the time taken then the body is moving with uniformly accelerated motion as it will follow Newton's second equation of motion for a particular initial velocity, which can be given by, s=ut+21at2.

hope this is helpful to you

3 0

3 years ago

What happens to the energy when the material is changed?

expeople1 [14]

Answer: When a material is heated or cooled, two changes may happen to the particles within the material: Chemical bonds between the particles may form, break or stretch. There is a change in the chemical potential store of energy in the material. The material will heat up or cool down as the particles within it gain or lose speed.

Explanation:

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3 years ago

A helicopter flies southeast with a ground speed of 250 km/h. If the wind

notsponge [240]

Answer:

C. 233 km/h

Explanation:

Ground speed = air speed + wind speed

250 km/h = v + 17 km/h

v = 233 km/h

4 0

3 years ago

Water flows through a water hose at a rate of Q1 = 860 cm3/s, the diameter of the hose is d1 = 1.85 cm. A nozzle is attached to

Snowcat [4.5K]

Answer:

a) A1 = $\frac{\pi (d1)^{2} }{4}$

b) A1 = 2.688 cm $^{2}$

c) Q1 = A1 x v1

d) v1 = 3.1994 m/s

e) A2 = $\frac{A1 X v1}{v2}$

f) A2 = 0.7963cm $^{2}$

Explanation:

a) Area = $\pi r^{2}$

r = $\frac{d}{2}$

thus,

area = $\pi (\frac{d}{2})^{2}$

A1 = $\frac{\pi (d1)^{2} }{4}[/tex]b) d1 = 1.85 cmsubstituting in the above equation,A1 = [tex]\frac{\pi (d1)^{2} }{4}$

A1 = $\frac{\pi (1.85)^{2} }{4}$

A1 = 2.688 cm $^{2}$

c) Flow rate = Area x velocity ( refer brainly.com/question/13997998)

Q1 = A1 x v1

d) From the above equation,

v1 = $\frac{Q1}{A1}$ = $\frac{860}{2.688}$ = 319.94 cm/s = 3.1994 m/s

e) Since the flow rate Q1 is constant throughout the hose, Av is a constant.

i.e. A1 x v1 = A2 x v2

thus,

A2 = $\frac{A1 X v1}{v2}$

f) v2 = 10.8 m/s.

substituting the values in the above equation,

A2 = $\frac{2.688 X 3.1994}{10.8}$ = 0.7963cm $^{2}$

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4 years ago

The wattage marked on a lightbulb is not an inherent property of the bulb but depends on the voltage to which it is connected, u

Mashutka [201]

Answer:

The current that flows through the lamp is 0.5 A.

Explanation:

A lamp functions like a resistor and the real power absorbed by a resistor is given by the product of the voltage drop across it's terminals and the current that flows through it. If we wish to find the current that this lamp draws we should divide the wattage given (60 W) by the voltage drop provided (120 V). We then have:

i = P/V = 60/120 = 0.5 A.

5 0

3 years ago