Please find attached photograph for your answer. Hope it helps. Please do comment
Newton’s first law of inertia
Less force, same work
Answer:
The value is the temperature of the air inside the tire
340.54 K
% of the original mass of air in the tire should be released 99.706 %
Explanation:
Initial gauge pressure = 2.7 atm
Absolute pressure at inlet
= 2.7 + 1 = 3.7 atm
Absolute pressure at outlet
= 3.2 + 1 = 4.2 atm
Temperature at inlet
= 300 K
(a) Volume of the system is constant so pressure is directly proportional to the temperature.


340.54 K
This is the value is the temperature of the air inside the tire
(b). Since volume of the tyre is constant & pressure reaches the original value.
From ideal gas equation P V = m R T
Since P , V & R is constant. So
m T = constant




value of the original mass of air in the tire should be released is

⇒ -0.99706
% of the original mass of air in the tire should be released 99.706 %.
Answer:
B. Axial stress divided by axial strain
Explanation:
Elasticity:
It is the tendency of an object to deform along the axis when an opposing force is applied without facing permanent change in shape.
Plasticity:
When an object crosses the elasticity limit, it enters plasticity where the change due to stress is permanent and the object might even break.
Yield strength:
Yield strength is the point of maximum bearable stress that indicates the limit of elasticity.
Our case:
As the stress applied is less than the yield strength, the rod is still in the elasticity state and its modulus can be calculated.
Modulus of Elasticity = Stress along axis/Ratio of change in length to original length
Axial strain is basically the ratio of change in length to original length.
So, Modulus of Elasticity = Axial Stress/ Axial Strain