Explanation:
Let us assume that the maximum allowable horizontal distance be represented by "d".
Therefore, torque equation about A will be as follows.
d = ![\frac{[2 \times 75 \times (0.7+0.15+0.15) - 60 \times 0.15 - 252 \times 0.15 \times 2]}{252}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B2%20%5Ctimes%2075%20%5Ctimes%20%280.7%2B0.15%2B0.15%29%20-%2060%20%5Ctimes%200.15%20-%20252%20%5Ctimes%200.15%20%5Ctimes%202%5D%7D%7B252%7D)
d = 0.409 m
Thus, we can conclude that the maximum allowable horizontal distance from the axle A of the wheelbarrow to the center of gravity of the second bag if she can hold only 75 N with each arm is 0.409 m.
Answer:
v = 3(m1 - 2m2)/(m1 + m2)
Explanation:
Parameters given:
Velocity of first toy car with mass m1, u1 = 3 m/s (taking the right direction as the positive axis)
Velocity of second toy car with mass m2, u2 = -6 m/s (taking the left direction as the negative x axis)
Using conservation of momentum principle:
Total initial momentum = Total final momentum
m1*u1 + m2*u2 = m1*v1 + m2*v2
Since they stick together after collision, they have the same final velocity.
m1*3 + (m2 * -6) = m1*v + m2*v
3m1 - 6m2 = (m1 + m2)v
v = (3m1 - 6m2) / (m1 + m2)
v = 3(m1 - 2m2) / (m1 + m2)
Answer:
540 J
Explanation:
U at top equals to K at bottom if it's an isolated system therefore U at top is equals to 540 J so we can assume that at 0m U=0 (mgh) therefore the box has gained some velocity due to the acceleration due to g and we can calculate it using 1/2mv²
Answer:
A gas is a sample of matter that conforms to the shape of a container in which it is held and acquires a uniform density inside the container, even in the presence of gravity and regardless of the amount of substance in the container.
Answer:
a) It moved to a lower potential
b) ΔФ = - 86.28 Volt
Explanation:
The energy of an charged particle and the electric potential are related by the potential al kinetic energies:
If we consider an electron:
m = 9.10938*10^-31 Kilogram
e = 1.60218*10^-19 Coulomb
And the potential diference may be calculed by:
Replacing all the values we get:
ΔФ = - 86.28 (Kilogram Meter^2)/(Coulomb Second^2) = -86.28 Volts
