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Vanyuwa [196]
3 years ago
5

The measured mass of a body is found to be 110g. The length is measured by a meter scale. Actual mass and length of the body are

100 g and 10 cm. Find the percentage error in the calculation of density.
Physics
1 answer:
Elan Coil [88]3 years ago
5 0

Answer:

ok it will be g+181

Explanation:

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A space probe is directly between two moons of a planet. If it is twice as far from moon A as it is from moon B, but the net for
Dennis_Churaev [7]

Answer:

c. Moon A is four times as massive as moon B

Explanation:

Let's assume the:

  • mass of the object = m\,kilogram
  • mass of the moon A = M_A\,kilogram
  • mass of the moon B = M_B\,kilogram
  • distance between the center of masses of the object and moon B = r\,meters

According to the given condition the object is twice as far from moon A as it is from moon B

  • ∴distance between the center of masses of the object and moon B = 2r\,meters

<u>As we know, gravitational force of attraction is given by:</u>

F=G\frac{m_1.m_2}{r^2}

<em>According to the condition</em>

Force on m due toM_B=Force on m due toM_A

G\frac{m.M_A}{(2r)^2} =G\frac{m.M_B}{(r)^2}

\frac{M_A}{4r^2} =\frac{M_B}{r^2}

M_A=4M_B

3 0
3 years ago
In 2007, michael carter (u.s.) set a world record in the shot put with a throw of 24.77 m. what was the initial speed of the sho
Serga [27]

The initial speed of the shot is 15.02 m/s.

The Shot put is released at a height y<em> </em>from the ground with a speed u. It is released at an angle θ to the horizontal. In a time t, the shot put travels a distance <em>R</em> horizontally.

Pl refer to the attached diagram.

Resolve the velocity u into horizontal and vertical components, u ₓ=ucosθ and uy=u sinθ. The horizontal component remains constant in the absence of air resistance, while the vertical component varies due to the action of the gravitational force.

Write an expression for R.

R=u_xt=(ucos \theta)t

Therefore,

t=\frac{R}{ucos\theta} .......(1)

In the time t, the net displacement of the shotput is y in the downward direction.

Use the equation of motion,

y=u_yt-\frac{1}{2}gt^2=(usin\theta) t-\frac{1}{2}gt^2

Substitute the value of t from equation (1).

y=(ucos\theta)(\frac{R}{ucos\theta} )-\frac{1}{2} g(\frac{R}{ucos\theta} )^2\\ =Rtan\theta-(\frac{gR^2}{2u^2cos^2\theta} )

Substitute -2.10 m for y, 24.77 m for R and 38.0° for θ and solve for u.

y=Rtan\theta-(\frac{gR^2}{2u^2cos^2\theta} )\\ (-2.10m)=(24.77 m)(tan38.0^o)-\frac{(9.8 m/s^2)(24.77m)^2}{2u^2(cos38.0^o)^2} \\ u^2=225.71(m/s)^2\\ u=15.02m/s

The shot put was thrown with a speed 15.02 m/s.




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2 years ago
A thin film of oil rests on an inclined plane
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What is the question?

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2 years ago
What will happen to the speed of an object if the net force is in the direction of the motion?
nata0808 [166]
The speed increases
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3 years ago
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Why is conserving energy resources not a simple problem with a simple solution?
anyanavicka [17]

Answer:

Because the uncontrolled and unreasonable use of energy resources in the past few decades has led to the depletion of conventional type of resources. Although, measures are taken at the government levels to control the energy consumption, these attempts only meet with little success. Public awareness is the only way to successfully deal with this problem.

Explanation:

6 0
3 years ago
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