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Alexxx [7]
3 years ago
10

What force is acting on a 2 kg apple falling on the Earth (g=10)

Physics
1 answer:
jolli1 [7]3 years ago
4 0

Answer:

An apple in free fall accelerates toward the Earth with a free fall acceleration, g. The force of the apple on the Earth also causes the Earth to accelerate toward the falling apple. By Newton's Third Law, the force of the Earth on the apple is exactly equal and opposite to the force of the apple on the Earth. By Newton,s Second law, the force of the Earth on the apple is equal to the mass of the apple times g , the accelerations due to gravity. And, the force of the the apple on the Earth is equal to the mass of the Earth times the acceleration of the Earth toward the apple. In conclusion, the magnitude of the forces are equal, or

F ( apple on the Earth) = F( the Earth on the apple) or

M( mass of the earth) x a( the acceleration of the earth toward the apple) = m(mass of the apple) x g( the acceleration of the apple toward the Earth) or

a = (m/M) g

Explanation:

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The solution would be like this for this specific problem:

 

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<span>v^2 = (0.0 m/s)^2 + [2 * (9.8 m/s^2) * (56 m) ] </span><span>
<span>v^2 = 2 * (9.8 m/s^2) * (56 m) </span>
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<span>v = SQRT {1,097.6 m^2/s^2 } </span></span>

v = 33.1 m/s

<span>v = u + at </span>

<span>(v - u) / a = t </span>

[ (33.1 m/s) - (0.0 m/s) ] / (9.8 m/s^2) = 3.38 seconds

If the pigeon is 56.0 m below the initial position of the falcon, it will take 3.38 seconds for the falcon to reach the pigeon. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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