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Andreas93 [3]
3 years ago
12

This chart shows characteristics of three different waves, all with the same wavelength of 10 m but moving at different Which st

atement is best supported by the information in the chart?
A 3-column table with 2 rows titled Waves at Different Frequencies. The first column has entries Wave X and 6 hertz. The second column has entries Wave Y and 0.5 hertz. The third column has entries Wave Z and 2 hertz.
Wave Y is moving the fastest.

Wave X is moving the fastest.

All of the waves are moving at the same speed.

All of the waves have the same value of wavelengths per second.
Physics
2 answers:
Ainat [17]3 years ago
7 0

Answer:

Wave X is moving the fastest.

JulijaS [17]3 years ago
3 0

Answer:

Wave X is moving the fastest.

Explanation:

As we know that the speed of the wave is given as the product of frequency and wavelength

so here we will have

\lambda = 10 m

now for wave X

f = 6 Hz

now the speed of this wave is

v_x = 10 \times 6 = 60 m/s

now for wave Y

f = 0.5 Hz

now the speed of this wave is

v_y = 10 \times 0.5 = 5 m/s

now for wave Z

f = 2 Hz

now the speed of this wave is

v_z = 10 \times 2 = 20 m/s

So correct answer will be

Wave X is moving the fastest.

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Skskdidododododoorrororo
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if a star 100 light years from earth is beginning to expand into a giant star how long will it take for astronomers to observe t
VikaD [51]

Answer:

100years later

Explanation:

Because the lights will arrive at world after 100 years later.

7 0
3 years ago
The Earth orbits the Sun at a speed of 30 km/s. At that speed it completes one path around the Sun every year. Of course, as tha
romanna [79]

Answer:

a. 299,792,458 m/s

Explanation:

Since the speed of light in a vacuum is invariant and has the value of 299,792,458 m/s, we would measure this value of 299,792,458 m/s for the speed of light from the star as it arrives on Earth.

3 0
3 years ago
A huge tank of glycerine with a density of 1.260 g/cm3 is vertically stationed on a platform which is 15 m above the ground. The
EleoNora [17]

Answer:

The tank is losing 4.976*10^{-4}  m^3/s

v_g = 19.81 \ m/s

Explanation:

According to the Bernoulli’s equation:

P_1 + 1 \frac{1}{2} \rho v_1^2 + \rho gh_1 = P_2 +  \frac{1}{2}  \rho v_2^2 + \rho gh_2

We are being informed that both the tank and the hole is being exposed to air :

∴ P₁ = P₂

Also as the tank is voluminous ; we take the initial volume  v_1 ≅ 0 ;

then v_2 can be determined as:\sqrt{[2g (h_1- h_2)]

h₁ = 5 + 15 = 20 m;

h₂ = 15 m

v_2 = \sqrt{[2*9.81*(20 - 15)]

v_2 = \sqrt{[2*9.81*(5)]

v_2= 9.9 \ m/s  as it leaves the hole at the base.

radius r = d/2  = 4/2 = 2.0 mm

(a) From the law of continuity; its equation can be expressed as:

J = A_1v_2

J = πr²v_2    

J =\pi *(2*10^{-3})^{2}*9.9

J =1.244*10^{-4}  m^3/s

b)

How fast is the water from the hole moving just as it reaches the ground?

In order to determine that; we use the relation of the velocity from the equation of motion which says:

v² = u² + 2gh ₂

v² = 9.9² + 2×9.81×15

v² = 392.31

The velocity of how fast the water from the hole is moving just as it reaches the ground is : v_g = \sqrt{392.31}

v_g = 19.81 \ m/s

4 0
3 years ago
Can someone help please
love history [14]

Answer:

The correct answer is 24.

Explanation:

4 0
3 years ago
Read 2 more answers
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