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Tema [17]
3 years ago
10

Can someone help please

Physics
2 answers:
sesenic [268]3 years ago
7 0

Answer:

Third Side = 24 units.

Explanation:

Let the third side be 'm'.

Use Pythagoras theorem,

x² + 10² = 26²

x² = 676 - 100

x² = 576

x = 24 units

love history [14]3 years ago
4 0

Answer:

The correct answer is 24.

Explanation:

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Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the eq
gayaneshka [121]

Answer:

The volume is decreasing at 160 cm³/min

Explanation:

Given;

Boyle's law,  PV = C

where;

P is pressure of the gas

V is volume of the gas

C is constant

Differentiate this equation using product rule:

V\frac{dp}{dt} +P\frac{dv}{dt} = \frac{d(C)}{dt}

Given;

\frac{dP}{dt} (increasing pressure rate of the gas) = 40 kPa/min

V (volume of the gas) =  600 cm³

P (pressure of the gas) = 150 kPa

Substitute in these values in the differential equation above and calculate the rate at which the volume is decreasing ( \frac{dv}{dt});

(600 x 40) + (150 x \frac{dv}{dt}) = 0

\frac{dv}{dt} = -\frac{(600*40)}{150} = -160 \ cm^3/min

Therefore, the volume is decreasing at 160 cm³/min

3 0
3 years ago
A 2.0 m conductor is formed into a square and placed in the horizontal A magnetic field is oriented above the horizontal with a
pashok25 [27]

Answer:

<h3>4.0Wb/m²</h3>

Explanation:

Magnetic flux Ф is expressed using the formula;

Ф = BA

B is magnetic field

A is the area of the square conductor

Given

B = 1.0T

A =L²

Area A = 2.0² = 4.0m²

Get the magnetic flux

Ф = 1.0 * 4.0m²

Ф = 4.0Wb/m²

Hence the magnetic flux through the conductor is 4.0Wb/m²

8 0
3 years ago
A student finds an unlabeled liquid container in his lab. He notices that the container has two liquids. Since the two liquids h
raketka [301]

Answer:

\rho = 1848.03 kg m^{-3}

Explanation:

given data:

density of water \rho = 1 gm/cm^3 = 1000 kg/m^3

height  of water  = 20 cm  =0.2 m

Pressure  p = 1.01300*10^5 Pa

pressure at bottom

P =  P_{fluid} + P_{h_2 o}

P   = P_{fluid}  + \rho g h

P_{fluid}  = P - \rho g h

                 = 1.01300*10^5 - 1000*0.2*9.8

                 = 99340 Pa

p_{fluid}  = P_{atm} + \rho g h_{fluid}                       h_[fluid} = 0.307m

99340 = 104900 + \rho *9.8*0.307

\rho = 1848.03 kg m^{-3}

5 0
4 years ago
Dose any one have a old nitro type account they don’t want<br>Ill power it up for you<br>Please
erica [24]

Answer:

no I dont sorry lol. ............

4 0
3 years ago
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The distance between two parallel wires carrying currents of 10 A and 20 A is 10 cm. Determine the magnitude and direction of th
Marianna [84]

Explanation:

It is given that,

Current in wire 1, I₁ = 10 A

Current in wire 2, I₂ = 20 A

Distance between wires, d = 10 cm = 0.1 m

Force per unit length is given by :

\dfrac{F}{l}=\dfrac{\mu_oI_1I_2}{2\pi r}

\dfrac{F}{l}=\dfrac{4\pi \times 10^{-7}\times 10\times 20}{2\pi \times 0.1}

\dfrac{F}{l}=0.0004\ N/m

\dfrac{F}{l}=4\times 10^{-4}\ N/m

So, the magnetic force acting per unit length of the wires 4\times 10^{-4}\ N/m. Since, the current is in same direction. So, the force is attractive in nature.

6 0
3 years ago
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