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Leto [7]
3 years ago
10

a horizontal force of 50N acts on a body of mass 20KG initially at rest and displaces it by striking it along the entire 20m pat

h. What has been the work done by said force?
Physics
1 answer:
Aneli [31]3 years ago
3 0

Answer:

1000 J

Explanation:

Work = force × distance

W = (50 N) (20 m)

W = 1000 J

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72 mL

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3 years ago
You are a member of an alpine rescue team and must project a box of supplies, with mass m, up an incline of constant slope angle
AlekseyPX

Answer:

v = \sqrt{2gh + \frac{2\mu_kgh}{tan\theta}}

Explanation:

When we push the box from the bottom of the incline towards the top then by work energy theorem we can say that

Work done by all the forces = change in kinetic energy of the system

- mgh - F_f (s) = 0 - \frac{1}{2}mv^2

here we know that

F_f = \mu_k mg cos\theta

also we know that the length of the incline is given as

s = \frac{h}{sin\theta}

now we have

- mgh - \mu_k mgcos\theta(\frac{h}{sin\theta}) = -\frac{1}{2}mv^2

so we have

v = \sqrt{2gh + \frac{2\mu_kgh}{tan\theta}}

3 0
3 years ago
What is the correct formula for power? A. Power = work / time B. Power = work * time C. Power = force * distance D. Power = work
steposvetlana [31]

Answer:

A. Power = Work / Time

Explanation:

Power is the amount of work done over time, or rather the rate of work, which is given by the unit of watts (W). Since work is defined by Force * Displacement, we can also say Power = Force * Displacement / Time.

3 0
3 years ago
Read 2 more answers
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