Here, we are required to determine which element has atoms with Valence electrons in a higher energy level than those of calcium.
The Valence electrons of the Caesium, Cs atoms has higher energy level than those of Calcium.
First, we need to determine the electronic configuration of each of the elements
- Therefore the Calcium electron configuration will be:
- 1s²2s²2p⁶3s²3p⁶4s²
- Therefore, for Cs Electron Configuration:
- 1s² 2s²2p⁶3s²3p⁶3d¹⁰ 4s²4p⁶4d¹⁰ 5s²5p⁶ 6s¹
- Therefore, For lithium, The electron configuration of lithium is :
- 1s²2s¹
- For oxygen, Therefore the O electron configuration will be:
- 1s²2s²2p⁴
- For bromine, the electronic configuration is 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁵
Among the elements in the option, the Valence electrons of the Caesium, Cs atoms has higher energy level than those of Calcium.
This is so because the only Valence electron of Cs is located in the 6s orbital and as such has the highest energy level amongst all of the elements.
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The main purpose of gel electrophoresis is to separate the molecules based on their different electric charge.
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Answer:
its terminal velocity is 19.70 m/s
the velocity of a 58.0-kg person hitting the ground, assuming no drag contribution in such a short distance is 8.85 m/s
Explanation:
Firstly,
given that
m = 580g = 0.58kg
Area A = 0.11 * 0.22 = 0.0242m
g = 9.8
idensity constant p = 1.21 kg/m^3
the terminal velocity of the sphere Vt is ;
Vt = √ ( 2mg / pCA)
we substitute
Vt = √ ( (2*0.58*9.8) / (1.21*1*0.0242)
Vt = √ (11.368 / 0.029282)
Vt = √ ( 388.22)
Vt = 19.70 m/s
its terminal velocity is 19.70 m/s
What will be the velocity of a 58.0-kg person hitting the ground, assuming no drag contribution in such a short distance?
The Velocity of the person is;
V2 = √ 2ax
V2 = √ ( 2 * 9.8 * 4 )
V2 = √ (78.4)
V2 = 8.85 m/s
the velocity of a 58.0-kg person hitting the ground, assuming no drag contribution in such a short distance is 8.85 m/s
An object with a constant pushing or pulling force is exerted on it is greater than the frictional force, than A. The object will accelerate.
Answer:
(a): Linear charge density of the circular arc =
(b): Surface charge density of the circular arc =
(c): Volume charge density of the sphere =
Explanation:
<h2><u>
Part (a):</u></h2>
<u>Given:</u>
- Total charge on the circular arc,
- Radius of the circular arc,
- Angle subtended by the circular arc,
We know, e is the elementary charge whose value is
Therefore,
Also, the length l of a circular arc is given as:
The linear charge density of the arc is defined as the charge per unit length of the arc.
<h2><u>
Part (b):</u></h2>
<u>Given:</u>
- Total charge on the circular disc,
- Radius of the circular disc,
Surface area of the circular disc,
The surface charge density of the disc is defined as the charge per unit area of the disc.
<h2><u>
Part (c):</u></h2>
<u>Given:</u>
- Total charge on the sphere,
- Radius of the sphere,
Volume of the sphere,
The volume charge density of the sphere is defined as the charge per unit volume of the sphere.