The purpose of an experiment is to LEARN the EFFECT of something.
The way you do that is to CHANGE the thing and see what happens.
You can change as many things as you want to. But If you change
TWO things and observe the result, then you don't know which one
of them caused the effect you see.
Or maybe BOTH of them working together caused it. You don't know.
So your experiment is not really much good. You need to do it again.
Answer:
1.68m/s^2
Explanation:
using V^2=U^2+2×a×s formula.
If,
(Final Velocity)V=45
(Initial Velocity)U=0 because it starts from rest
(Distance)S=600m
(acceleration)a= ?
now,
using formula,
45^2=0^2+2×a×600
2025= 1200a
a=2025÷1200
a = 1.68m/s^2(The unit of acceleration is m/s^2)
Therefore the acceleration is 1.68m/s^2
Hope it works !!!
Electron volts...........
Answer:
The magnifying power of this telescope is (-60).
Explanation:
Given that,
The focal length of the objective lens of an astronomical telescope, 
The focal length of the eyepiece lens of an astronomical telescope, 
To find,
The magnifying power of this telescope.
Solution,
The ratio of focal length of the objective lens to the focal length of the eyepiece lens is called magnifying of the lens. It is given by :


m = -60
So, the magnifying power of this telescope is 60. Therefore, this is the required solution.