While the ball is held 20 meters above the floor,
Potential energy = (mass) (gravity) x (height) =
(0.5 kg) x (9.8 m/s²) x (20 m) = 98 joules.
When it's dropped and reaches 1/2 of its initial height, it has half as much
potential energy. The rest has turned into kinetic energy = <em>49 joules.
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Want to know what else you can figure out ? Watch this . . .
<u> Kinetic energy = (1/2) x (mass) x (speed)²</u>
49 joules = (1/2) x (0.5 kg) x (speed)²
Divide each side by (0.25 kg): 49 joules / 0.25 kg = speed²
Take the square root of each side: 7/0.5 = speed = <em><u>14 meters per second</u></em>
That's the speed of the ball after falling 10 meters !
How cool is that !
Answer:
a. 
b. 
Explanation:
The data given are
Height,h=550ft,
length of incline plane, L=1.50 miles
first we convert all parameters to meters
since 1ft=0.3048m then 550ft will be 167.76m
also 1mile=1609.34m, hence 1.5mile will be 2414m
From the diagram attached, the length and height formed a simple triangle with the length being the hypotenuse and the height being the opposite.
Hence using SOHCAHTOA, we can conclude that the angle will be
b. the new height becomes
going by the same formula, we solve the new length s
<span>disconformity is the correct answer
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