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3 years ago

The point beneath surface where rock breaks and an arthquake is produced is known as the

Physics

1 answer:

hjlf3 years ago

6 0

The point beneath surface where rock breaks and an earthquake is produced is known as the Focus.

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What is the initial velocity of the object represented by the graph?

Arturiano [62]

Initial velocity of the object: 5 m/s

Explanation:

The figure in the problem is missing: find it in attachment.

The graph in the figure represents the velocity of an object (v) versus the time passed (t).

Here we are asked to find the initial velocity of the object.

This means that we have to find the velocity of the object when the time is zero, so when

t = 0

By looking at the corresponding value on the y-axis (velocity), we see that when t = 0, then

v = 5 m/s

Therefore, the initial velocity of the object is 5 m/s.

Learn more about velocity:

brainly.com/question/5248528

#LearnwithBrainly

5 0

3 years ago

Read 2 more answers

Will mark as brainliest . pls help

ipn [44]

Answer:

answer D

Explanation:

circuit breaker is useful when you do something with your domestic electric circuit..

3 0

3 years ago

The rubber and plastic used in protective clothing do not allow the flow of electric charge

erica [24]

Answer:

True

Explanation:

Insulators are the material that does not allow electricity to pass easily through them. The reason behind using an insulator as a protective layer on an electrical wire or appliances is that they show good resistance to electricity. That prevents us from getting an electrical shock. And rubber and plastics are good examples of the insulator.

Hence our statement is true.

6 0

3 years ago

Three point charges, -4.7 x 10-9 C, -9.7 x 10-9 C, and 7.2 x 10-9 C, are fixed at different positions on a circle. The total ele

irinina [24]

Answer:

Explanation:

q1 = - 4.7 x 10^-9 C

q2 = - 9.7 x 10^-9 C

q3 = 7.2 x 10^-9 C

Potential at the centre of the circle, V = - 1900 V

Let the radius of the circle is r.

So, the potential is given by

$V = \frac{Kq_{1}}{r}+\frac{Kq_{2}}{r}+\frac{Kq_{3}}{r}$

$- 1900 = \frac{9\times 10^{9}}{r}\left ( - 4.7 - 9.7 + 7.2 \right )\times 10^{-9}$

$- 1900 = \frac{-9\times 7.2}{r}$

r = 0.034 m = 3.4 cm

6 0

3 years ago

Calculate the force of friction for a 5kg aluminum block being pulled with constant velocity (uniform motion) across a horizonta

Stolb23 [73]

The purpose of this lab is to determine whether the surface of an area would affect the coefficient of Friction. My classmates and I have learned a lot in this lab and that there could have been some errors in our lab because the strength of how a person pulls it might be a slight different than the normal force. I learned from this lab that the <span>surface area would have no effect on the coefficient of friction. </span>

4 0

2 years ago