Answer:
The magnitude is 63 kg m²/s, and the direction is -k.
Explanation:
Plug the values into the equation:
L = m v×r
L = (3.0 kg) (<5 i + 3j> m/s × <2i − 3j> m)
Take the cross product. The cross product of two dimensional vectors is:
<v₁ i + v₂ j> × <r₁ i + r₂ j> = <(v₁ r₂ − v₂ r₁) k>
Therefore:
L = (3.0 kg) <((5)(-3) − (3)(2)) k m²/s>
L = (3.0 kg) <-21 k m²/s>
Multiply:
L = <-63 k kg m²/s>
The magnitude is 63 kg m²/s, and the direction is -k.
When we drop the stone in air then during its motion in air the net force on the stone is due to gravity
so its net force is given as
here we know that
so we have
now as soon as it will enter into the water then it will have resistive force due to water as well as buoyant force due to water on it in opposite direction
so the net force on the stone will decrease
so as soon as it will enter into the water the acceleration of stone will decrease due to which the rate of increase in speed of the stone will decrease as it will enter into the water
Answer:
Light
Explanation:
The ability of light to exist as a wave and have particle-like properties is known as the wave-particle duality nature of light.
Light exist as a transverse electro-magnetic wave and also as a particle due to the fact that it contains photons and it emits electrons when it bombards a surface. This is known as photoelectric effect.
Number 3 is B.
number 4 is A.
number 5 is C.
What you really want to know is:
What is the net force ACTING ON the book ?
The answer is:
Before you ask how much net force there is, you should decide if there IS any net force.
-- If there's any net force acting on the object, then the object is accelerating.
-- If the object is not accelerating, then there is no net force acting on it.
-- The book is just laying there on the table. It is not accelerating. So there is definitely NO net force acting on it.
