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Westkost [7]
3 years ago
15

What is the volume of water in 150ml of the 35% w/w of sucrose solution with a specific gravity of 1.115?

Physics
1 answer:
pentagon [3]3 years ago
7 0

Answer:108.71 mL

Explanation:

Given

Volume of sample V=150 mL

concentration of sucrose solution 35 % w/w i.e. In  100 gm of sample 35 gm is sucrose

specific gravity =1.115

Density of solution \rho _s=1.115\times density\ of\ water

Thus

\rho _s=1.15\times 1 gm/mL=1.115\ gm/mL

mass of sample M=1.115\times 150=167.25\ gm

mass of sucrose m_s=0.35\times 167.25=58.53\ gm

mass of Water m_w=108.71 gm

Volume of water =108.71\times 1=108.781 mL

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marysya [2.9K]

Answer:

the limbic system has its input and processing side (the limbic cortex, amygdala and hippocampus) and an output side (the septal nuclei and hypothalamus).

Explanation:

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A wheel rotating about a fixed axis has a constant angular acceleration of 4.0 rad/s2. In a 4.0-s interval the wheel turns throu
anastassius [24]

Answer:

a. 3 s.

Explanation:

Given;

angular acceleration of the wheel, α = 4 rad/s²

time of wheel rotation, t = 4 s

angle of rotation, θ = 80 radians

Apply the kinematic equation below,

\theta = \omega_1 t \ + \ \frac{1}{2} \alpha t^2\\\\80 = 4\omega_1 + \frac{1}{2}*4*4^2\\\\80 = 4\omega_1 + 32\\\\ 4\omega_1 = 48\\\\ \omega_1 = \frac{48}{4}\\\\ \omega_1 = 12 \ rad/s

Given initial angular velocity, ω₀ = 0

Apply the kinematic equation below;

\omega_1 = \omega_o + \alpha t_1\\\\12 = 0 + 4t\\\\4t = 12\\\\t = \frac{12}{4}\\\\t = 3 \ s

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a. 3 s.

8 0
3 years ago
A constant net torque is applied to a rotating object. Which of the following best describes the object's motion? A constant net
ahrayia [7]

Answer:

The object will rotate with constant angular acceleration

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Answer:

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b) In a parallel connection, the link or relationship between the number of bulbs(resistors) is as the number of light bulbs increases, the current in the power pack (circuit) increases.

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