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dimulka [17.4K]
3 years ago
5

Which of the following best describes what occurs in a fusion reaction?

Physics
1 answer:
lutik1710 [3]3 years ago
4 0

Answer:

In the process some of the mass of the hydrogen is converted into energy. ... The sun and stars do this by gravity.

Explanation:

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In an elastic collision, a 300 kg bumper car collides directly from behind with a second, identical bumper car that is traveling
evablogger [386]

Answer:

If we had:

v_{1i}=5.3m/s

v_{2i}=5.9m/s

We will have:

v_{1f}=5.9m/s

v_{2f}=5.3m/s

Explanation:

In an elastic collision both linear momentum and kinetic energy are conserved, so we will have:

p_i=p_f

K_i=K_f

We will call our bumpers 1 and 2.

For the momentum equation we know that:

m_1v_{1i}+m_2v_{2i}=m_1v_{1f}+m_2v_{2f}

Since all the masses are the same (300kg), they cancel out:

v_{1i}+v_{2i}=v_{1f}+v_{2f}

For the kinetic energy equation we know that:

\frac{m_1v_{1i}^2}{2}+\frac{m_2v_{2i}^2}{2}=\frac{m_1v_{1f}^2}{2}+\frac{m_2v_{2f}^2}{2}

Since all the masses are the same (300kg), they cancel out (and also the 2 dividing):

v_{1i}^2+v_{2i}^2=v_{1f}^2+v_{2f}^2

We then must solve this system:

v_{1i}+v_{2i}=v_{1f}+v_{2f}

v_{1i}^2+v_{2i}^2=v_{1f}^2+v_{2f}^2

Which we will rewrite as:

v_{1i}-v_{1f}=v_{2f}-v_{2i}

v_{1i}^2-v_{1f}^2=v_{2f}^2-v_{2i}^2

The last of these equations can be written as:

(v_{1i}+v_{1f})(v_{1i}-v_{1f})=(v_{2f}+v_{2i})(v_{2f}-v_{2i})

But we know that v_{1i}-v_{1f}=v_{2f}-v_{2i}, so those cancel out:

v_{1i}+v_{1f}=v_{2f}+v_{2i}

So we can write:

v_{1i}-v_{1f}+v_{2i}=v_{2f}

v_{1i}+v_{1f}-v_{2i}=v_{2f}

Which means:

v_{1i}-v_{1f}+v_{2i}=v_{1i}+v_{1f}-v_{2i}

Which solving for the final velocity leaves us with:

v_{2i}+v_{2i}=+v_{1f}+v_{1f}

v_{1f}=v_{2i}

Grabbing any equation that relates both final velocities easily, for example v_{1i}-v_{1f}+v_{2i}=v_{2f}, we obtain:

v_{2f}=v_{1i}-v_{1f}+v_{2i}=v_{1i}-v_{1f}+v_{1f}=v_{1i}

So we conclude that the bumpers have just exchanged velocities (something sometimes seen in billiards for example):

v_{1f}=v_{2i}=5.9m/s

v_{2f}=v_{1i}=5.3m/s

3 0
3 years ago
Your roommate is working on his bicycle and has the bike upside down. He spins the 68.0 cm -diameter wheel, and you notice that
MAVERICK [17]

Answer:

a. 6.41 m/s

b. 120.85 m/s^2

Explanation:

The computation is shown below:

a. Pebble speed is

As we know that according to the tangential speed,

v = r \times \omega

= \frac{0.68}{2} \times  18.84

= 6.41 m/s

The 18.84 come from

=  2 \times 3.14 \times 3

= 18.84

b. The pebble acceleration is

a = \frac{v^2}{r}

= \frac{6.41^2}{0.34}

= 120.85 m/s^2

We simply applied the above formulas so that the pebble speed and the pebble acceleration could come and the same is to be considered

3 0
3 years ago
As a new electrical technician, you are designing a large solenoid to produce a uniform 0.160-T magnetic field near the center o
MariettaO [177]

Answer:

Current = 32.6 A

Explanation:

Magnetic field = B = 0.160 T

No. of turns of coil = N = 4300

Length of the solenoid = L = 1.10 m

Current required depends on the B, L , N and the magnetic permeability μ₀

B =  μ₀ N I / L

⇒ Current =  I = B L /  μ₀N = ( 0.160 ) ( 1.10) / (4π × 10⁻⁷)(4300)

                                           =  32.6 A

   

5 0
3 years ago
A lunar module (LM) lifts off from the lunar surface and flies a powered trajectory to its burnout point at 30 km altitude. The
xxTIMURxx [149]

Answer:

Detailed solution is given below:

7 0
3 years ago
A car takes 9 m to stop after the driver applies the brakes.
andrezito [222]

Depends upon how soon you want to stop. You know the mass of the car, you know the initial velocity of 8.9 m/s. You know the final velocity which is zero. You can now calculate the deceleration of the car if you know how soon you want to stop.

Let's say you want to stop in one second.

a = (vf - vi) / t = - 8.9 m/s^2 (negative sign indicates deceleration).

F = ma = 800 x 8.9 = 7120 Newtons (kg*m/s^2)

4 0
2 years ago
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