Answer:
Three long wires are connected to a meter stick and hang down freely. Wire 1 hangs from the 50-cm mark at the center of the meter stick and carries 1.50 A of current upward. Wire 2 hangs from the 70-cm mark and carries 4.00 A of current downward. Wire 3 is to be attached to the meterstick and to carry a specific current, and we want to attach it at a location that results ineach wire experiencing no net force.
(a) Determine the position of wire 3.
b) Determine the magnitude and direction of current in wire 3
Explanation:
a)
position of wire = 50 - 1.2
= 48.8cm
b)
Direction ⇒ downward
Density is calculated as mass per unit volume. In this case, since the material has a mass of 47 grams and we have the volume of 15 cm^3, we can simply divide the values:
Density = 47 grams / 15 cm^3 = 3.1 g/cm^3
Therefore, the material has a density of 3.1 g/cm^3
I think is altitude because tbh it don’t even mean nothing
Answer:
D.
Explanation: Both have shapes determined by gravitational forces.
Answer:
the impulse experienced by this object is 4 Ns
Explanation:
Given;
mass of the object, m = 3 kg
velocity of the object, v = 4 m/s
resistive force, F = 20 N
duration of impact, t = 0.2 s
The impulse experienced by this object is calculated as follows;
J = F x t
J = 20 x 0.2
J = 4 Ns
Therefore, the impulse experienced by this object is 4 Ns