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S_A_V [24]
3 years ago
8

Hybrid seeds are deliberately crossbred for particular traits, such as growth pattern or disease resistance. They have been hand

-pollinated and are patented, often sterile, and genetically identical within food types. These plants are usually grown in a monocultural environment and are cultivated for mass production and sale. They must be sturdy to withstand mechanical picking and cross-country shipping. They do not compare to the quality and taste of heirloom plants, but they do produce large, healthy fruit that appeals to most shoppers. Unlike heirloom seeds, if one saves a hybrid seed, one will not get the same plant again.
Which statement can be removed and not affect the excerpt’s reliability?
Physics
1 answer:
Lena [83]3 years ago
7 0

Answer:

Unlike heirloom seeds, if one saves a hybrid seed, one will not get the same plant again.

Explanation:

The statement that can be removed without affecting the reliability of overall paragraph is, "unlike heirloom seeds, if one saves a hybrid seed, one will not get the same plant again". <em>This is because even if we remove this line, the paragraph still looks completely understandable, reliable and in a flow.</em>

If we talk about hybrid plants, we know that they are produced through cross pollination of the crops with desired traits. Although they are sterile and cannot produce offspring, however the plants which are raised from these seeds are edible and quite healthy. This is why these plants have better yield and a better resistance against environmental constraints like diseases and stresses. After the production, hybrid seeds are stored and they are able to produce plants of similar types.

Hope it helps!

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How many infrared photons of frequency 2.57 x 1013 Hz would need to be absorbed simultaneously by a tightly bound molecule to br
victus00 [196]

Answer:

94

Explanation:

f = 2.57 x 10^13 Hz

E = 10 eV = 10 x 1.6 x 10^-19 J = 1.6 x 10^-18 J

Energy of each photon = h f

Where, h is Plank's constant

Energy of each photon = 6.63 x 10^-34 x 2.57 x 10^13 = 1.7 x 10^-20 J

Number of photons = Total energy / energy of one photon

N = (1.6 x 10^-18) / (1.7 x 10^-20) = 94.11 = 94

6 0
3 years ago
How could I tell if an egg is hard boiled or raw explain using Newton's law of motion
Thepotemich [5.8K]

Answer:

Explanation:

Newton's 2 nd law of motion tells that when equal torque is applied on object having higher moment of inertia , it will rotate slower .

Moment of inertia of boiled egg is higher because the whole egg rotates as s solid unit . Hence it will rotate slower or it rolls slower on an inclined surface .

In this way by applying Newton's law , we can identify raw or boiled egg .

6 0
3 years ago
You play basketball in your driveway during the summer. By accident, you leave the basketball outside during the winter. You try
daser333 [38]
Slower and the pressure is heavier in the winter
3 0
3 years ago
Read 2 more answers
Why does a lorry travelling at 30mph have more kinetic energy than a car travelling at the same velocity?
rjkz [21]

Answer:

Because it has more mass

Explanation:

To understand this, think about the equation of kinetic energy

KE = \frac{1}{2} m v^{2}

Kinetic energy depends on both the velocity (v) as well as the mass (m).

Because a lorry is bigger and heavier than a car, it will have more mass. With more mass, at the same velocity the lorry with have more kinetic energy.

5 0
3 years ago
A ball of radius r rolls on the inside of a track of radius R. If the ball starts from rest at the vertical edge of the track, f
meriva

Answer:

v=\sqrt{\dfrac{10g(R-r)}{7}}

Explanation:

Given that

Radius of track = R

Radius of ball = r

The ball can be treated as solid sphere, so

The moment of inertia of ball

I=\dfrac{2}{5}mr^2

When the ball reach at the lowest position then it will have both angular and linear speed.

Condition for  rolling without slipping       v= ωr

Form energy conservation

mgR=mgr+\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2

 v= ωr

I=\dfrac{2}{5}mr^2

mgR=mgr+\dfrac{1}{2}mv^2+\dfrac{1}{2}\times \dfrac{2}{5}mr^2\omega^2

mg(R-r)=\dfrac{1}{2}mv^2+\dfrac{1}{2}\times \dfrac{2}{5}mv^2

2mg(R-r)=mv^2+\dfrac{2}{5}mv^2

2g(R-r)=\dfrac{7}{5}v^2

v=\sqrt{\dfrac{10g(R-r)}{7}}

3 0
3 years ago
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