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coldgirl [10]
3 years ago
5

Which of the following statements is true? A) A counting semaphore can never be used as a binary semaphore. B) A binary semaphor

e can never be used as a counting semaphore. C) Spinlocks can be used to prevent busy waiting in the implementation of semaphores. D) Counting semaphores can be used to control access to a resource with a finite number of instances.
Mathematics
1 answer:
saveliy_v [14]3 years ago
5 0

Answer:

C

Step-by-step explanation:

Statement C of the following statements is true

C). Spin-locks can be used to prevent busy waiting in the implementation of semaphore.

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What is the equation of the line that best fits the given data? A graph has points (1, 7), (1, 6), (2, 5), (2.5, 5), (3, 3), (4,
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answer is d

Step-by-step explanation:

hope it is helpful

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Ashley bought 2 CD's for $15 each and a charger for 7.50. If she writes a check for $45.94, What is the sales tax rate?
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3 years ago
Complete each congruency statement and name the rule used. If you cannot show the triangles are congruent from the given informa
irinina [24]

Answer:

The correct answer is;

ΔANT ≅ ΔFLE by the SIde-Side-Side (SSS) rule of congruency

Step-by-step explanation:

The given information are;

Segment TN is congruent ts segment EL

Segment TA is congruent ts segment EF

Segment AN is congruent ts segment FL

Therefore, triangle ΔANT is congruent to ΔFLE by the Side-Side-Side (SSS) rule of congruency

One of the rule used to serve as proof that two or more triangles are congruent, is the Side-Side-Side (SSS) rule of congruency. The Side-Side-Side rule of congruency states that if the dimensions of the three sides of one triangle are equal to the dimensions of the three sides of another triangle, the two triangles are congruent.

Therefore, the correct option is ΔANT ≅ ΔFLE by the Side-Side-Side (SSS) rule of congruency

7 0
3 years ago
Tan 3A in terms of tan​
Zanzabum

Here's the sum rule for the tangent function:

\tan(a+b)=\dfrac{\tan(a)+\tan(b)}{1-\tan(a)\tan(b)}

In the special case a=b, this becomes the double angle formula:

\tan(a+a)=\tan(2a)=\dfrac{\tan(a)+\tan(a)}{1-\tan(a)\tan(a)}=\dfrac{2\tan(a)}{1-\tan^2(a)}

In your case, you case use the sum rule once:

\tan(3a)=\tan(2a+a)=\dfrac{\tan(2a)+\tan(a)}{1-\tan(2a)\tan(a)}

And use it again, in the special case of the double angle:

\dfrac{\dfrac{2\tan(a)}{1-\tan^2(a)}+\tan(a)}{1-\dfrac{2\tan(a)}{1-\tan^2(a)}\tan(a)}

We can obvisouly simplify this expression a lot: let's deal with the numerator and denominator separately: the numerator is

\dfrac{2\tan(a)}{1-\tan^2(a)}+\tan(a) = \dfrac{2\tan(a)+\tan(a)-\tan^3(a)}{1-\tan^2(a)}

and the denominator is

1-\dfrac{2\tan(a)}{1-\tan^2(a)}\tan(a) = \dfrac{1-\tan^2(a)-2\tan^2(a)}{1-\tan^2(a)} = \dfrac{1-3\tan^2(a)}{1-\tan^2(a)}

So, the fraction is

\dfrac{2\tan(a)+\tan(a)-\tan^3(a)}{1-\tan^2(a)}\cdot \dfrac{1-\tan^2(a)}{1-3\tan^2(a)} = \dfrac{2\tan(a)+\tan(a)-\tan^3(a)}{1-3\tan^2(a)}

8 0
4 years ago
Which of the following exponential functions go through the points (1,12) and (2,36)?
Ratling [72]

Answer:

D

Step-by-step explanation:

Evaluate both points into each equation and see which works out..

A:  f(1) = 4(3)^-1 = 4/3, it's supposed to be 12, so this equation is ruled out

B:  f(1) = 3(4)^-1 = 3/4, ruled out for the same reason as A

C:  f(1) = 3(4)^1 = 12, this works, now check the 2nd point...

    f(2) = 3(4)² = 3(16) = 48, it's supposed to be 36, so this equation is ruled out

D:  f(1) = 4(3)^1 = 12, this works, now check the 2nd point..

    f(2) = 4(3)² = 4(9) = 36, this is what we wanted.  

6 0
3 years ago
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