The most common injuries in a chemistry lab is making a fire, heat burns, chemical burns, cuts and scrapes, contamination, inhalation, and spills and breaks.
1.) You can prevent making a fire by making sure you close and seal flammable materials.
2.) You can prevent heat burns by teaching the students how to properly use tongs,water baths, and other cooling equipment.
3.) You can prevent chemical burns by treating the chemicals with caution, measure carefully, and use the approved containers.
4.) You can prevent cuts and scrapes by telling the students how to use the blades safely, and also when they are disposing broken or sharp items they should know how to wrap them up so no one else will get hurt.
5.) You can prevent contamination by washing your hands, protect their clothing and skin with a lab coat or a lab apron, gloves and glasses, and cleaning your area where the germs of the chemicals were so no one will become.
6.) You can prevent inhalation by opening up windows, using ventilation fans, and using an equipment that measures the amount of gas emission in a room.
7.) Finally, you can prevent spills and breaks by telling the students what will happen if anything spills, and tell them to clean up.
Releasing the string would most likely increase the kinetic energy, as kinetic energy is energy in motion. However, if you were to increase the potential energy, then the string would have to be pulled back more, as potential energy is stored energy within an object.
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<span>Formed when two or more atoms chemically bond together, the resulting compound is unique both chemically and physically from its parent atoms</span>
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Answer:
0.0253 M/s
Explanation:
From the reaction
N₂ + 3H₂ → 2NH₃
The rate of reaction can be written as
Rate = - = - = +
From the above rate equation we can conclude that the rate of reaction of N₂ is equal to one third of the rate of reaction of H₂,
So,
Rate of reaction of molecular nitrogen =
Upon calculation, we get rate of reaction of molecular nitrogen = 0.0253 M/s
Chlorine. i think it has one less electron.... i'm not sure though.