The graph that shows the proportional relationship y = 0.7x is Graph A.
<h3>What is a proportional relationship?</h3>
A proportional relationship is a function in which the output variable is given by the input variable multiplied by a constant of proportionality, that is:
y = kx
In which k is the constant of proportionality.
In this problem, 7 out of 10 customers preferred the restaurants new spaghetti sauce, hence the constant is given by:
k = 7/10 = 0.7.
And the equation is:
y = 0.7x.
When x = 0, y = 0, which already eliminates graphs C and D. When x = 10, y = 7, which means that Graph A is the answer to this question.
More can be learned about proportional relationships at brainly.com/question/10424180
Answer:
107.5
Step-by-step explanation:
make d the subject by multiplying both sides by t,d=St . convert 43m to kilometers to get speed in km/hr then multiply it by time (2.5)=0.1075.convert into metres
Answer:
The area of the composite figure is 392.12
.
Step-by-step explanation:
The area of the composite figure = area of trapezoid + area of rectangle
Area of trapezium = 
( a +b)h
Where: a is the length of the first base, b the length of the second base and h is the height of the trapzium.
Applying Pythagoras theorem, the height, h, is;
h = 
= 
h = 2
Area of trapezium = ( a +b)h
= (13 + 12) × 2
= 156
= 382.12
Area of trapezium is 382.12
Area of rectangle = length × width
= 5 × 2
= 10
Area of rectangle = 10
Therefore,
area of the composite figure = 382.12 + 10
= 392.12
The equations that represent linear relationship is y – 5 = 2(x – 1)
<h3 /><h3>What are linear functions</h3>
Linear functions are functions that has a leading degree of 1. According to the question, we need to determine the function that represents linear equation.
The required equation must have a degree of 1 and must contain both dependent and independent variables.
The equations that represent linear relationship is y – 5 = 2(x – 1)
Learn more on linear function here: brainly.com/question/4025726
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Answer:
3x square-30x +29=0. i think thats the equatiom
