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yarga [219]
3 years ago
12

You’ve set up a frictionless car racetrack, with a loop of radius 0.5 m. Your toy car of mass 2 kg starts at rest at the top of

a ramp and is released so that it slides down and approaches the loop. What condition must be present so that the car just completes the loop? How high must you make the ramp in order to complete the loop?
Physics
1 answer:
Anna007 [38]3 years ago
4 0

Answer

h = 1.12 m

Explanation:

given,

mass of the car = 2 kg

radius = 0.5 m

let h be the height of the ramp

when the car reaches at the top point

gravity = centripetal force  

mg =\dfrac{mv^2}{r}

g =\dfrac{v^2}{r}

v = \sqrt{gr}

using conservation of energy

\PE_i = PE_f + KE_f

m g h = m g (2r)+\dfrac{1}{2}mv^2

g h =g (2r)+\dfrac{1}{2}(\sqrt{gr})^2

g h =2 gr +\dfrac{gr}{2}

h =\dfrac{5r}{2}

h =\dfrac{5\times 0.5}{2}

h = 1.12 m

hence, height of the ramp should be greater than  1.12 m so that it can complete the loop.

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Answer:

The kinetic energy is: 50[J]

Explanation:

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The elevation is 10 [m], and at this point the ball is having only potential energy, the kinetic energy is zero.

E_{p} =m*g*h\\where:\\g= gravity[m/s^{2} ]\\m = mass [kg]\\m= \frac{E_{p} }{g*h}\\ m= \frac{100}{9.81*10}\\\\m= 1.01[kg]\\\\

In the moment when the ball starts to fall, it will lose potential energy and the potential energy will be transforme in kinetic energy.

When the elevation is 5 [m], we have a potential energy of

P_{e} =m*g*h\\P_{e} =1.01*9.81*5\\\\P_{e} = 50 [J]\\

This energy is equal to the kinetic energy, therefore

Ke= 50 [J]

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Answer:

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Explanation:

The given data is as follows.

      F = 3.2 N,      m = 18.2 kg,

      t = 0.82 sec

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          I = Ft = \Delta P

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Putting the given values into the above formula as follows.

      v_{f} = \frac{Ft}{m} + v_{i}

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Therefore, final velocity of the mass if it is initially at rest is 0.144 m/s.

(b)  When velocity is 1.85 m/s to the left then, final velocity of the mass will be calculated as follows.

           Ft = m(v_{f} - v_{i})

or,      v_{f} = \frac{Ft}{m} + v_{i}

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