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Nataly [62]
3 years ago
13

If the person drops box from 3.8 m how much energy is transferred from potential energy to kinetic energy

Physics
1 answer:
kotykmax [81]3 years ago
8 0

Answer:

Kinetic energy

When work is done the energy is transferred from one type to another. This transferred energy may appear as kinetic energy.

For example, when you pedal your bicycle so that its speed increases, you are doing work to transfer chemical energy from your muscles to the kinetic energy of the bicycle.

Kinetic energy is the energy an object possesses by virtue of its movement. The amount of kinetic energy possessed by a moving object depends on the mass of the object and its speed. The greater the mass and the speed of the object the greater its kinetic energy.

The kinetic energy Ek of an object of mass m at a speed v is given by the relationship

{E_k} = \frac{1}{2}m{v^2}

m is the mass of the object in kilograms ( kg) and v is the speed of the object in metres per second ( m\,s^{-1}).

Explanation:

When work is done on an object it may also lead to energy being transferred to the object in the form of gravitational potential energy of the object.

Gravitational potential energy is the energy an object has by virtue of its position above the surface of the Earth. When an object is lifted, work is done. When work is done in raising the height of an object, energy is transferred as a gain in the gravitational potential energy of the object.

For example, suppose you lift a suitcase of mass m through a height h. The weight W of the suit case is a downward force of size mg. In lifting the suitcase, you would have to pull upwards on it with a force equal in size to its weight, mg.

Two suitcases. One has a green force arrow pointing up labelled F and a purple force arrow pointing down labelled 'Weight = mg'. The other case is raised by a height labelled h.

Suitcases with forces and height labelled

When this force (equal to the weight mg, but upwards) is applied to the suitcase over the distance h:

Work\,done=force\,\times\,distance\,upwards=mg\,\times\,h

This energy is transferred to potential energy when raising the object through a known height.

Energy = mass \times gravitational\,field\,strength \times height

E = m \times g \times h

This is the relationship used to calculate gravitational potential energy.

{E_p} = mgh

where m is the mass of the object in kilograms (kg), g is the gravitational field strength, (for positions near the surface of the Earth g = 9∙8 newtons per kilogram ( N kg ^{-1} and h is the height above the surface of the Earth in metres ( m).

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Calculate the force needed to bring a 950-kg car to rest from a speed of 90.0 km/h in a distance of 120 m (a fairly typical dist
WINSTONCH [101]

Answer:

a)

2474 N

b)

148438 N

Explanation:

(a)

v₀ = initial velocity of the car = 90 km/h = 25 m/s

v = final velocity of the car = 0 m/s

d = stopping distance for the car = 120 m

F = force needed to bring the car to rest

m = mass of the car = 950 kg

Using Work-change in kinetic energy theorem

F d Cos180 = (0.5) m (v² - v₀²)

F (120) (-1) = (0.5) (950) (0² - 25²)

F = 2474 N

b)

v₀ = initial velocity of the car = 90 km/h = 25 m/s

v = final velocity of the car = 0 m/s

d = stopping distance for the car = 2 m

F = force needed to bring the car to rest

m = mass of the car = 950 kg

Using Work-change in kinetic energy theorem

F d Cos180 = (0.5) m (v² - v₀²)

F (2) (-1) = (0.5) (950) (0² - 25²)

F = 148438 N

6 0
3 years ago
Please help with this :(
kiruha [24]

Answer:

Below

Explanation:

We can use this formula to find the acceleration of the crate :

     acceleration = net force / mass of object

Plug in our values :

     acceleration = 50 N / 50 kg

                           = 1 m/s^2

     acceleration = 100 N / 50 kg

                           = 2 m/s^2

     acceleration = 150 N / 50 kg

                           = 3 m/s^2

     acceleration = 200 N / 50 kg

                           = 4 m/s^2

Hope this helps! Best of luck <3

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Answer:

Explanation:

Density = mass/volume

132g/(48.9 cm³) = 2.7 g/cm³

(27 g)/(3 cm³) = 9 g/cm³

512 g/(65 cm³) = 7.9 g/cm³

1.2 kg/(3243 cm³) cm³ = 1200 g/(3243 cm³) = 0.37 g/cm³

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