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3 years ago

What is an non-example of a switch

Physics

1 answer:

loris [4]3 years ago

3 0

Dont really understand what youre asking but switches can be used to turn things on and off.

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A spring whose stiffness is 980 N/m has a relaxed length of 0. 50 m. If the length of the spring changes from 0. 25 m to 0. 81 m

Gelneren [198K]

151.9j

Explanation:

PE=1/2kx^2

PE=1/2(980)(.50)= 245j

PE=(1/2)(980)(.81)= 396.9j

396.9- 245= 151.9j

8 0

2 years ago

The hard disk's surface is scratched and some or all of the data is destroyed when there is a _______.

AveGali [126]

When the surface of a hard disk is scratched an some or all of the files are destroyed, it is called a head crash. It is a result of a disk in contact with the rotating platter causing it to permanently damage a very sensitive part of the disk.

3 0

3 years ago

OSCilloscope shows wave starts cycle minimum 20 units reaches max of 100 units before completing 5 milliseconds what is relation

Vitek1552 [10]

Answer:

$T=0.02\ s$

$f=50\ Hz$

Explanation:

Given:

minimum amplitude at the start of oscillation cycle, $a_0=20\ unit$

the first maximum amplitude after the start of oscillation cycle, $a_{m1}=100\ units$

Time taken to reach from the first minima to the first maxima, $t=5\times 10^{-3}\ s$

As we know that an oscilloscope executes a wave cycle represented by a sine wave. So we can deduce that it has executed one-fourth of the cycle in going from the amplitude of 20 units to 100 units in 0.005 seconds.

So the time taken to complete one cycle of the oscillation:

$T=4\times 0.005$

$T=0.02\ s$ is the time period of the oscillation

We know frequency:

$f=\frac{1}{T}$

$f=\frac{1}{0.02}$

$f=50\ Hz$

6 0

4 years ago

What’s the kinetic energy of the object? Use .

kirill115 [55]

We have: K.E. = mv² / 2
here, m = 4 Kg
v = 9 m/s

Substitute their values into the expression:
K.E. = (4)(9)² / 2
K.E. = (4)(81) / 2
K.E. = 324 / 2
K.E. = 162 Joules

In short, Your Answer would be 162 J

Hope this helps!

5 0

3 years ago

Read 2 more answers

If an otherwise empty pressure cooker is filled with air of room temperature and then placed on a hot stove, what would be the m

Xelga [282]

Answer:

The magnitude of the net force F₁₂₀ on the lid when the air inside the cooker has been heated to 120 °C is $\frac{135.9}{A}N$