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Stella [2.4K]
2 years ago
14

Convection currents in this layer drive the tectonic plates above them.

Physics
1 answer:
Sphinxa [80]2 years ago
7 0

Hello, hello? Hey! Hey, wow, day 4. I knew you could do it.

Uh, hey, listen, I may not be around to send you a message tomorrow. *banging* It's-It's been a bad night here for me. Um, I-I'm kinda glad that I recorded my messages for you *clears throat* uh, when I did.

Uh, hey, do me a favor. *banging* Maybe sometime, uh, you could check inside those suits in the back room? *banging* I'm gonna to try to hold out until someone checks. Maybe it won’t be so bad. *bang bang* Uh, I-I-I-I always wondered what was in all those empty heads back there. *chime plays*.

You know...*deep moan* oh, no - *noises followed by a loud screech and static*

Explanation:

You might be interested in
The treasure map gives the following directions to the buried treasure ​
iren2701 [21]

Answer:

North

South

East

West

Explanation:

please mark me as brainliest

3 0
2 years ago
A dart hits a dartboard and stops in 0.060 s. The net force on the dart is 14 N during the collision.
Rainbow [258]

Answer:

<em>The change of momentum of the dart is 0.84 Nw.s</em>

Explanation:

<u>Impulse and change of momentum</u>

The change in momentum of an object is its mass times the change in its velocity:

\Delta p=m\Delta v=m(v_2-v_1)

The change in the momentum can also be found by considering the force acting on it. If a force F acts for a time Δt, the change of momentum is given by:

\Delta p=F.\Delta t

The dart hits a dashboard with a net force of 14 N during the collision and stops in 0.06 seconds. The change of momentum is:

\Delta p=14*0.06=0.84

The change of momentum of the dart is 0.84 Nw.s

5 0
3 years ago
Why do objects that are thrown or shot follow a curved path
LenaWriter [7]
The initial force of the throw overcomes gravity quite easily. Then, gravity begins to bring it back down to earth, making a curved path.

8 0
3 years ago
I need the answers to these questions if u dont mind
Nonamiya [84]
there’s no photo. brainly hasent been working for me today so not sure
3 0
2 years ago
Erase all the trajectories, and fire the pumpkin vertically again with an initial speed of 14 m/s. As you found earlier, the max
yanalaym [24]

Answer:

\theta=39.49^{\circ}

Explanation:

Maximum height of the pumpkin, H_{max}=9.99\ m

Initial speed, v = 22 m/s

We need to find the angle with which the pumpkin is fired. the maximum height of the projectile is given by :

H_{max}=\dfrac{v^2\ sin^2\theta}{2g}

On rearranging the above equation, to find the angle as :

\theta=sin^{-1}(\dfrac{\sqrt{2gH_{max}}}{v})

\theta=sin^{-1}(\dfrac{\sqrt{2\times 9.8\times 9.99}}{22})

\theta=39.49^{\circ}

So, the angle with which the pumpkin is fired is 39.49 degrees. Hence, this is the required solution.

8 0
2 years ago
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