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3 years ago

The reaction forms 15.9g of Ag(s). 2Ag2O(s)→4Ag(s)+O2(

1 answer:

3 0

You will use PV=nRT

First, water vapor pressure at 25°C is 23.8 mmHg. Subtract this from the total pressure to get 733.2 mmHg. Convert to atm to get 0.965 atm.

15.9g of Ag = .147 mole Ag

25°C +273.15 = 298.15K

Plug in the values.

(.965atm)V = (.147mol)(.08206 L*atm/mol*K)(298.15K) = 3.7 L

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Be sure to answer all parts. What can be added to the equilibrium AgCl(s) + 2NH3(aq) ⇌ Ag(NH3)2+(aq) + Cl−(aq) (a) that will shi

lora16 [44]

Answer:

a) Ag(NH₃)₂⁺, Cl⁻.

b) NH₃.

c) AgCl.

Explanation:

Based on LeChatelier's law, a system in chemistry can change responding to a disturbance of concentration, temperature, etc. in order to restore a new state.

In the reaction:

AgCl(s) + 2NH₃(aq) ⇌ Ag(NH₃)₂⁺(aq) + Cl⁻(aq)

When reactants are added, the system will produce more products restoring the equilibrium and vice versa. A reactant in solid state doesn't take part in the equilibrium, thus:

a) Ag(NH₃)₂⁺, Cl⁻. The addition of products will shift the equilibrium to the left

b) NH₃. The addition of reactant will shift the equilibrium to the right.

c) As AgCl is in solid phase, will not shift the equilibrium in either direction.

6 0

3 years ago

What are the things to consider in classifying the different kinds of mixture?

algol13

Answer:

Whether the mixture can be separated

4 0

4 years ago

Calculate Δ H o for the reaction. CH3OH + HCl → CH3Cl + H2O answer is in kJ/mol .

Nimfa-mama [501]

Answer:

$\Delta H=-28.08 \frac{kJ}{mol}$

Explanation:

Hello,

This types of reactions are likely to be carried out in gaseous phase as it is easier to induce reactions, therefore, for us to compute the change in the enthalpy of this reaction we should write the formation enthalpy of gaseous methanol, hydrogen chloride, methyl chloride and water as -205.1, -92.3, -83.68 and -241.8 kJ/mol respectively. Then, the reaction enthalpy for this reaction is:

$\Delta H=\Delta _fH_{CH_3Cl}+\Delta _fH_{H_2O}-\Delta _fH_{CH_3OH}-\Delta _fH_{HCl}\\\\\Delta H=-83.68\frac{kJ}{mol}-241.8\frac{kJ}{mol}-(-205.1\frac{kJ}{mol})-(-92.3\frac{kJ}{mol} )\\\\\Delta H=-28.08 \frac{kJ}{mol}$

Which accounts for an exothermic chemical reaction.

Regards.

7 0

4 years ago

The four fundamental forces are arranged in the increasing order of their relative strength.

Sonbull [250]

Answer:

Both weak interaction and strong interaction act only between non-atomic particles.

Explanation:

Arrange the four fundamental forces in increasing strength:

Gravity,
"Weak" interaction,
Electromagnetic interaction, and
Strong interaction.

Thus, this question is about the strong and weak interactions. In particular, the choices are concerned about properties common to both types of interactions.

The ranges of electromagnetic interaction and gravity are infinite. However, the ranges of strong and weak interactions are much smaller. The maximum range of weak interactions is around $\rm 10^{-16}\; m$ . The maximum range of strong interactions is around $\rm 10^{-15}\;m$ .

Weak interaction occurs between left-hand fermions. This class of particles includes neutrinos, which do not carry any charge. The most energetic strong interactions occur between quarks, which are all charged. Some of the weaker residual strong interactions occur between particles that are made of quarks. That includes both protons and neutrons (which do not carry any charge.) This type of strong interaction holds nuclei intact.

Consider the choices:

The range of neither weak nor strong interactions is infinite. This range is smaller than the radius of atomic nuclei.
Strong and weak interactions indeed act between charged particles. However, there are exceptions such as neutrinos and neutrons.
The ranges of strong and weak interactions are so small that they are nearly undetectable outside of atomic nuclei. Both interactions act only between non-atomic particles such as protons and neutrons as well as electrons and quarks.
Atoms are too large to experience weak and strong interactions.

6 0

3 years ago

In the embden-meyerhof pathway, one mole of _____ is converted into two moles of pyruvic acid.

Blababa [14]

The answer that best fits the blank provided above is the term GLUCOSE. The E<span>mbden-Meyerhof-Parnas pathway is a type of glycolysis, therefore, glucose is being converted in this process. Every mole of glucose is converted into two moles of pyruvic acid. Hope this helps.</span>

5 0

3 years ago