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vladimir1956 [14]
3 years ago
10

The reaction forms 15.9g of Ag(s). 2Ag2O(s)→4Ag(s)+O2(

Chemistry
1 answer:
BaLLatris [955]3 years ago
3 0
You will use PV=nRT

First, water vapor pressure at 25°C is 23.8 mmHg. Subtract this from the total pressure to get 733.2 mmHg. Convert to atm to get 0.965 atm.

15.9g of Ag = .147 mole Ag

25°C +273.15 = 298.15K

Plug in the values.

(.965atm)V = (.147mol)(.08206 L*atm/mol*K)(298.15K) = 3.7 L
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The number of ions in 17.1 gm of aluminum sulphate Al2 (SO4)3 =….. [Molar mass of Al2 (SO4)3 = 342 gm]
katen-ka-za [31]

Answer:

1.51 X 10^23 ions

Explanation:

The number of ions in 17.1 gm of aluminum sulphate Al2 (SO4)3 =….. [Molar mass of Al2 (SO4)3 = 342 gm]

in one molecule of Al2(SO4)3 there are 5 ions 2 aluminum and 3 sulfate ions

in 2 molecules there are 2X5= 10 ions

in 10 molecules there are 10X5 = 50 ions

molar mass of Al2(SO4)3 = (2 X 26.98) +( 3 X 32.1) + (3 X 4 X 16.0 ) =342.gms = 17.1/342 =0.0500 moles

1  mole =6.02 X 10^23 molecules ( see Avogadros number)

0.0500 moles = 0.0500 X 6.02 X 10^23 molecules =

0.301 X 10^23 molecules = 3.01 X 10^22 molecules

We determined that each molecule of Al2(SO4)3 has 5 ions

so 3.01 X10^22 molecules have 5 X 3.01 X 10^22 ions =

15.05 X 10^22 ions = 1.51 X 10^23 ions

3 0
3 years ago
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olasank [31]
At the same velocity
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A solution of zinc nitrate is added to a solution of magnesium sulfate. express your answer as a chemical equation. identify all
alexandr402 [8]

Answer is: no reaction occurs, because all salts are soluble in water.

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Ionic reaction:  

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8 0
3 years ago
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sashaice [31]

Answer:

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Hydrogen has an oxidation state of 1 and oxygen has an oxidation state of −2 when they are present in most compounds. (Exceptions to this are that hydrogen has an oxidation state of −1 in hydrides of active metals, e.g. LiH, and oxygen has an oxidation state of −1 in peroxides, e.g. H2O2 the algebraic sum of oxidation states of all atoms in a neutral molecule must be zero, while in ions the algebraic sum of the oxidation states of the constituent atoms must be equal to the charge on the ion.

The same is written in my textbook. But how am I supposed to find the ox. number of an atom, which is in compound like K2UO4?

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