Question

The reaction forms 15.9g of Ag(s). 2Ag2O(s)→4Ag(s)+O2(

Answer 1

You will use PV=nRT

First, water vapor pressure at 25°C is 23.8 mmHg. Subtract this from the total pressure to get 733.2 mmHg. Convert to atm to get 0.965 atm.

15.9g of Ag = .147 mole Ag

25°C +273.15 = 298.15K

Plug in the values.

(.965atm)V = (.147mol)(.08206 L*atm/mol*K)(298.15K) = 3.7 L